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2.3x= 10.312+8.274
2.3x = 10.(33)4+ (33)4 . 8
2.3x= (33)4. 18
2.3x= (33)4.2.32
2.3x= 312+2.2
2.3x= 314.2
=> x = 14
a) \(\left(19x+2\cdot5^2\right):14=\left(13-8\right)^2-4^2\)
\(\left(19x+2\cdot5^2\right):14=9\)
\(19x+2\cdot5^2=9\cdot14=126\)
\(19x+50=126\)
\(19x=126-50=76\)
\(x=\frac{76}{19}=4\)
b) \(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=1240\)
\(\left(x+x+..+x\right)+\left(1+2+3+...+30=1240\right)\)(31 chữ số x)
\(31x+\frac{30\cdot31}{2}=1240\Leftrightarrow31x+465=1240\)
\(31x=1240-465=775\)
\(x=\frac{775}{31}=25\)
c) \(11-\left(-53+x\right)=97\)
\(11+53-x=97\Leftrightarrow64-x=97\)
\(x=64-97=-33\)
d) \(-\left(x+81\right)+213=-16\)
\(-x-81+213=-16\)
\(-x+132=-16\)
\(-x=-16-132=-148\)
\(x=148\)
..........
a) \(\frac{3}{7}-\frac{1}{7}x=\frac{2}{3}\)
=> \(\frac{1}{7}x=\frac{3}{7}-\frac{2}{3}=-\frac{5}{21}\)
=> \(x=-\frac{5}{21}:\frac{1}{7}=-\frac{5}{21}\cdot7=-\frac{5}{3}\)
b) \(3x^2-2=72\)=> 3x2 = 74 => x2 = 74/3 => x không thỏa mãn
c) \(\left(19x+2\cdot5^2\right):14=\left(13-8\right)^2-4^2\)
=> \(\left(19x+2\cdot25\right):14=5^2-4^2=9\)
=> \(\left(19x+50\right):14=9\)
=> \(19x+50=126\)
=> \(19x=76\)
=> x = 4
d) \(x:\frac{1}{2}+x:\frac{1}{4}+x:\frac{1}{8}+x:\frac{1}{16}+x:\frac{1}{32}=343\)
=> \(x\cdot2+x\cdot4+x\cdot8+x\cdot16+x\cdot32=343\)
=> \(x\left(2+4+8+16+32\right)=343\)
=> x . 62 = 343
=> x = 343/62
\(3^2.3^x.81-27^4=0\)
\(3^2.3^x.3^4-\left(3^3\right)^4=0\)
\(3^6.3^x-3^{12}=0\)
\(3^6.3^x-3^{12}=0\)
\(3^6.3^x=0+3^{12}\)
\(3^6.3^x=3^{12}\)
\(3^{6+x}=3^{12}\)
\(\Rightarrow6+x=12\)
\(x=12-6\)
\(\Rightarrow x=6\)
\(2^{x+1}=4=2^2\Rightarrow x+1=2\Rightarrow x=1\)
\(2^{x-1}=4=2^2\Rightarrow x-1=2\Rightarrow x=3\)
\(2^x.4=128=4.32=4.2^5\Rightarrow x=5\)
\(3^{x-2}.9=81=9.9=9.3^2\Rightarrow x-2=2\Rightarrow x=4\)
\(\frac{3^{x+1}}{9}=3\Rightarrow3^{x+1}=27=3^3\Rightarrow x=2\)
\(41-2^x=9\Rightarrow2^x=41-9=32=2^5\Rightarrow x=5\)
Quá 20h rồi không biết được ko
3^x-2.9=81
3^x-2=81:9
3^x-2=9
3^x=9+2
3^x=11
3^x= tap hop rong
Suy ra x = tap hop rong
còn bài cuối thì sao bn