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NV
Nguyễn Việt Lâm
Giáo viên
1 tháng 3 2022
\(\dfrac{1}{21}+\dfrac{1}{28}+...+\dfrac{2}{x\left(x+1\right)}=\dfrac{2}{9}\)
\(\Leftrightarrow\dfrac{2}{42}+\dfrac{2}{56}+...+\dfrac{2}{x\left(x+1\right)}=\dfrac{2}{9}\)
\(\Leftrightarrow\dfrac{2}{6.7}+\dfrac{2}{7.8}+...+\dfrac{2}{x\left(x+1\right)}=\dfrac{2}{9}\)
\(\Leftrightarrow2\left(\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{8}+...+\dfrac{1}{x}-\dfrac{1}{x+1}\right)=\dfrac{2}{9}\)
\(\Leftrightarrow\dfrac{1}{6}-\dfrac{1}{x+1}=\dfrac{1}{9}\)
\(\Leftrightarrow\dfrac{1}{x+1}=\dfrac{1}{6}-\dfrac{1}{9}\)
\(\Leftrightarrow\dfrac{1}{x+1}=\dfrac{1}{18}\)
\(\Leftrightarrow x+1=18\)
\(\Leftrightarrow x=17\)
TL
3
3 tháng 6 2017
\(\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+...+\frac{2}{x.\left(x+1\right)}=\frac{2}{9}\)
\(\frac{2}{42}+\frac{2}{56}+\frac{2}{72}+...+\frac{2}{x.\left(x+1\right)}=\frac{2}{9}\)
\(\frac{2}{6.7}+\frac{2}{7.8}+\frac{2}{8.9}+...+\frac{2}{x.\left(x+1\right)}=\frac{2}{9}\)
\(2.\left(\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+...+\frac{1}{x.\left(x+1\right)}\right)=\frac{2}{9}\)
\(2.\left(\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+...+\frac{1}{x}-\frac{1}{x-1}\right)=\frac{2}{9}\)
\(2.\left(\frac{1}{6}-\frac{1}{x-1}\right)=\frac{2}{9}\)
\(\frac{1}{6}-\frac{1}{x-1}=\frac{2}{9}:2\)
\(\frac{1}{6}-\frac{1}{x-1}=\frac{1}{9}\)
\(\frac{1}{x-1}=\frac{1}{6}-\frac{1}{9}\)
\(\frac{1}{x-1}=\frac{1}{18}\)
\(\Rightarrow x-1=18\)
\(\Rightarrow x=18+1\)
\(\Rightarrow x=19\)
3 tháng 6 2017
= 2/42 + 2/56+2/72+................+2/x.(x+1)=2/9
=\(\frac{2}{6.7}\)+\(\frac{2}{7.8}\)+\(\frac{2}{8.9}\)+......+\(\frac{2}{x.\left(x+1\right)}\)=2/9
=2.( \(\frac{1}{6}\)-\(\frac{1}{7}\)+\(\frac{1}{7}\)-\(\frac{1}{8}\)+.......+\(\frac{1}{x}\)-\(\frac{1}{x+1}\)
=2.(1/6 -\(\frac{1}{x+1}\))=2/9
=1/6 -\(\frac{1}{x+1}\)=2/9:2=1/9
=1/6-1/9=\(\frac{1}{x+1}\)=3/54=1/18
=> x= 18-1 =17
TS
12 tháng 3 2015
mình trả lời bài 1 thôi nhé :
Gọi biểu thức trên là A.
Theo bài ra ta có:A=1/1.6+1/6.11+1/11.16+...+1/(5n+1)+1/(5n+6)
=1/5(1-1/6+1/6-1/11+1/11-1/16+...+1/5n+1-1/5n+6)
=1/5(1-1/5n+6)
=1/5( 5n+6/5n+6-1/5n+6)
=1/5(5n+6-1/5n+6)
=1/5.5n+5/5n+6
=n+1/5n+6
=ĐIỀU PHẢI CHỨNG MINH
30 tháng 4 2015
x- 20/11.13 - 20/13.15 - 20/13.15 - 20/15.17 -...- 20/53.55=3/11
x-10.(2/11.13+2/13.15+2/15.17+...+2/53.55=3/11
x-10.(1/11-1/13+1/13-1/15+1/15-1/17+...+1/53-1/55)=3/11
x-10.(1/11-1/55)=3/11
x-10.4/55=3/11
x-8/11=3/11
x = 3/11+8/11
x=11/11=1
****
22 tháng 4 2018
Ta có :
\(\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+...+\frac{2}{x\left(x+1\right)}=\frac{2}{9}\) ( cái đề hình như có 1 phân số \(\frac{2}{9}\) đúng không bạn )
\(\Leftrightarrow\)\(\frac{2}{42}+\frac{2}{56}+\frac{2}{72}+...+\frac{2}{x\left(x+1\right)}=\frac{2}{9}\)
\(\Leftrightarrow\)\(2\left(\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+...+\frac{1}{x\left(x+1\right)}\right)=\frac{2}{9}\)
\(\Leftrightarrow\)\(\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+...+\frac{1}{x\left(x+1\right)}=\frac{1}{9}\)
\(\Leftrightarrow\)\(\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+...+\frac{1}{x\left(x+1\right)}=\frac{1}{9}\)
\(\Leftrightarrow\)\(\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{1}{9}\)
\(\Leftrightarrow\)\(\frac{1}{6}-\frac{1}{x+1}=\frac{1}{9}\)
\(\Leftrightarrow\)\(\frac{1}{x+1}=\frac{1}{6}-\frac{1}{9}\)
\(\Leftrightarrow\)\(\frac{1}{x+1}=\frac{1}{18}\)
\(\Leftrightarrow\)\(x+1=1:\frac{1}{18}\)
\(\Leftrightarrow\)\(x+1=18\)
\(\Leftrightarrow\)\(x=18-1\)
\(\Leftrightarrow\)\(x=17\)
Vậy \(x=17\)
Chúc bạn học tốt ~
PD
0
DT
0
0
2
AK
30 tháng 4 2018
\(\frac{1}{15}+\frac{1}{21}+...+\frac{2}{x.\left(x+1\right)}=\frac{806}{2015}\)
\(\Rightarrow2.\left(\frac{1}{30}+\frac{1}{42}+...+\frac{1}{x.\left(x+1\right)}\right)=\frac{806}{2015}\)
\(\Rightarrow2.\left(\frac{1}{5.6}+\frac{1}{6.7}+...+\frac{1}{x.\left(x+1\right)}\right)=\frac{806}{2015}\)
\(\Rightarrow2.\left(\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{x}-\frac{1}{x+1}\right)=\frac{806}{2015}\)
\(\Rightarrow2.\left(\frac{1}{5}-\frac{1}{x}\right)=\frac{806}{2015}\)
\(\Rightarrow\frac{1}{5}-\frac{1}{x}=\frac{806}{2015}:2\)
\(\Rightarrow\frac{1}{5}-\frac{1}{x}=\frac{403}{2015}\)
\(\Rightarrow\frac{1}{x}=\frac{1}{5}-\frac{403}{2015}\)
\(\Rightarrow\frac{1}{x}=\frac{403}{2015}-\frac{403}{2015}\)
\(\Rightarrow\frac{1}{x}=0\)
\(\Rightarrow x=0\)
Vậy \(x=0\)
Chúc bạn học tốt !!!!
F
30 tháng 4 2018
\(\Rightarrow\frac{1}{2}\left(\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+...+\frac{2}{x\left(x+1\right)}\right)=\frac{806}{2015}.\frac{1}{2}\)
\(\Rightarrow\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+...+\frac{1}{x\left(x+1\right)}=\frac{403}{2015}\)
\(\Rightarrow\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+...+\frac{1}{x\left(x+1\right)}=\frac{403}{2015}\)
\(\Rightarrow\frac{6-5}{5.6}+\frac{7-6}{6.7}+\frac{8-7}{7.8}+...+\frac{x+1-x}{x\left(x+1\right)}=\frac{403}{2015}\)
\(\Rightarrow\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{403}{2015}\)
\(\Rightarrow\frac{1}{5}-\frac{1}{x+1}=\frac{403}{2015}\)
\(\Rightarrow\frac{1}{x+1}=\frac{1}{5}-\frac{403}{2015}\)
rồi bạn tự giải nốt nhé
2 tháng 4 2016
1/21 = 2/42 = 1/7-1/8
1/28 = 2/56 = 1/8-1/9
.....
1/(x*(x+1)) = 1/x -1/(x+1)
cộng lại với nhau ta sẽ được 1/7 - 1/(x+1) = 2/9
suy ra 1/(x+1) = -5/62 :D
1/21 +1/28 +1/36 ...2/x (x+1)=2/9
=>1/3.7 +1/4.7+1/4.9 ....2/x.(x+1)=2/9
=>2/6.7+2/7.8+2/8.9....+2/x.(x+1)=2/9
=>2.(1/6-1/x+1)=2/9
=>1/6 - 1/x +1 =1/9
=>1/x + 1 =1/18
=>x+1=18
=>x=17
DS:17
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