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\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)
\(\frac{11}{13}-\frac{5}{42}+x=-\frac{15}{28}+\frac{11}{13}\)
\(\frac{-5}{42}+x=-\frac{15}{28}+\left(\frac{11}{13}-\frac{11}{13}\right)\)
\(\frac{-5}{42}+x=-\frac{15}{28}\)
\(x=-\frac{15}{28}+\frac{5}{42}\)
\(x=-\frac{45}{84}+\frac{10}{84}\)
\(x=-\frac{35}{84}\)
Vậy \(x=-\frac{35}{84}\).
\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=\frac{113}{364}\)
\(\left(\frac{5}{42}-x\right)=\frac{11}{13}-\frac{113}{364}\)
\(\left(\frac{5}{42}-x\right)=\frac{15}{28}\)
\(x=\frac{5}{42}-\frac{15}{28}\)
\(x=-\frac{5}{12}\)
vậy \(x=-\frac{5}{12}\)
A) 7/38 x 9/11 +7/38 x 4/11 -7/38 x 2/11
=7/38.(9/11+4/11-2/11)
=7/38
B) 5/31 x 21/25 + 5/31 x -7/10 - 5/31 x 9/20
=5/31.(21/25-7/10-9/20)
=5/31.(-31/100)
=-1/20
\(\frac{1}{13}-\left(\frac{5}{42}-x\right)=-\left(-\frac{113}{364}\right)\)
=>\(\frac{1}{13}-\frac{5}{42}+x=\frac{113}{364}\)
=>\(-\frac{23}{546}+x=\frac{113}{364}\)
=>\(x=\frac{113}{364}-\left(-\frac{23}{546}\right)\)
=>\(x=\frac{113}{364}+\frac{23}{546}\)
=>\(x=\frac{55}{156}\)
\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=\frac{113}{364}\)
\(\left(\frac{5}{42}-x\right)=\frac{11}{13}-\frac{113}{364}\)
\(\left(\frac{5}{42}-x\right)=\frac{15}{28}\)
\(x=\frac{5}{42}-\frac{15}{28}\)
\(x=-\frac{5}{12}\)
vậy \(x=-\frac{5}{12}\)
a ) | x + 1/3 | = 5/6
+) x + 1/3 = 5/6 hay x + 1/3 = -5/6
x = 5/6 - 1/3 x = -5/6 - 1/3
x = 1/2 x =-7/6
b ) 11/13 - ( 5/42 - x ) = - ( 15/28-11/13 )
11/13 - ( 5/42 - x ) = 113/364
( 5/42 - x ) = 11/13 - 113/364
( 5/42 - x ) = 15/28
x = 5/42 - 15/28
x = -5/12
c ) | x |/186 = ( 1 - 303030 / 313131 ) + ( 616161 / 626262 - 1 )
| x | / 186 = 1/62
| x | = 1/62 . 186
| x | = 3
x = 3 hoặc -3
1) \(\left(-1\dfrac{1}{5}+x\right):\left(-3\dfrac{3}{5}\right)=\dfrac{-7}{4}+\dfrac{1}{4}:\dfrac{1}{8}\)
\(\Leftrightarrow\left(-1\dfrac{1}{5}+x\right):\left(-3\dfrac{3}{5}\right)=\dfrac{-7}{4}+2\)
\(\Leftrightarrow\left(-1\dfrac{1}{5}+x\right):\left(-3\dfrac{3}{5}\right)=\dfrac{1}{4}\)
\(\Leftrightarrow-1\dfrac{1}{5}+x=\dfrac{1}{4}.\left(-3\dfrac{3}{5}\right)\)
\(\Leftrightarrow-1\dfrac{1}{5}+x=\dfrac{1}{4}.\left(-\dfrac{18}{5}\right)\)
\(\Leftrightarrow-1\dfrac{1}{5}+x=-\dfrac{9}{10}\)
\(\Leftrightarrow x=\left(-\dfrac{9}{10}\right)-\left(-1\dfrac{1}{5}\right)\)
\(\Leftrightarrow x=\dfrac{3}{10}\)
Bài làm:
a) \(\left(\frac{2x}{7}-5\right)\div\left(-8\right)=0,75\)
\(\Leftrightarrow\frac{2x}{7}-5=-6\)
\(\Leftrightarrow\frac{2x}{7}=-1\)
\(\Leftrightarrow x=-\frac{7}{2}\)
b) \(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)
\(\Leftrightarrow x+\frac{11}{13}-\frac{5}{42}=\frac{11}{13}-\frac{15}{28}\)
\(\Rightarrow x=-\frac{5}{7}\)