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a) x - (17 - 8) = 5 + (10 - 3x)
x - 17 + 8 = 5 + 10 - 3x
x + 3x = 5 + 10 + 17 - 8
4x = 24
x = 24 : 4
x = 6
b) 25 - (30 + x) = x - (27 - 8)
25 - 30 - x = x - 27 + 8
-x - x = -27 + 8 - 25 + 30
-2x = -14
x = (-14) : (-2)
x = 7
c) (x - 12) - 15 = (20 - 7) - (18 + x)
x - 12 - 15 = 20 - 7 -18 - x
x + x = 20 - 7 - 18 + 12 + 15
2x = 22
x = 22 : 2
x = 11
d) 9 - 25 = (7 - x) - (25 + 7)
9 - 25 = 7 - x - 25 - 7
x = 7 - 25 - 7 - 9 +25
x = -9
a) 3x – 15 = 25 – 5x
=> 3x + 5x = 25 + 15
=> 8x = 40
=> x = 5
b) 3x - 17 = 2x – 7
=> 3x - 2x = -7 + 17
=> x = 10
c) 2x – 17 = – (3x – 18)
=> 2x - 17 = -3x + 18
=> 2x + 3x = 18 + 17
=> 5x = 35
=> x = 7
d) 3x – 14 = 2(x – 9) + 1
=> 3x - 14 = 2x - 18 + 1
=> 3x - 2x = -18 + 1 + 14
=> x = -3
f) (x – 5)2 = 9
\(\Rightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)
a) Ta có: \(3x-15=25-5x\)
\(\Leftrightarrow3x-15-25+5x=0\)
\(\Leftrightarrow8x-40=0\)
\(\Leftrightarrow8x=40\)
hay x=5
Vậy: x=5
b) Ta có: \(3x-17=2x-7\)
\(\Leftrightarrow3x-17-2x+7=0\)
\(\Leftrightarrow x-10=0\)
hay x=10
Vậy: x=10
c) Ta có: \(2x-17=-\left(3x-18\right)\)
\(\Leftrightarrow2x-17=-3x+18\)
\(\Leftrightarrow2x-17+3x-18=0\)
\(\Leftrightarrow5x-35=0\)
\(\Leftrightarrow5x=35\)
hay x=7
Vậy: x=7
d) Ta có: \(3x-14=2\left(x-9\right)+1\)
\(\Leftrightarrow3x-14=2x-18+1\)
\(\Leftrightarrow3x-14-2x+18-1=0\)
\(\Leftrightarrow x+3=0\)
\(\Leftrightarrow x=-3\)
Vậy: x=-3
f) Ta có: \(\left(x-5\right)^2=9\)
\(\Leftrightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)
Vậy: \(x\in\left\{2;8\right\}\)
a. x - (17 - 8) = 5 + (10 - 3x)
=> x - 9 = 5 + 10 - 3x
=> x + 3x = 15 + 9
=> 4x = 24
=> x = 6
b. 25 - (30 + x) = x - (27 - 8)
=> 25 - 30 - x = x - 19
=> -x -x = -19 + 30 - 25
=> -2x = -14
=> x = 7
c. (x - 12) - 15 = (20 - 7) - (18 + x)
=> x - 12 - 15 = 13 - 18 - x
=> x + x = 13 - 18 + 12 + 15
=> 2x = 22
=> x = 11
1)tính
a)\(-17+\left(-19\right)+25\)
\(=-17-19+25\)
\(=-\left(17+19\right)+25\)
\(=-36+25\)
\(=-\left(36-25\right)\)
\(=-11\)
b)\(-26+\left(-25\right)-18\)
\(=-26-25-18\)
\(=-\left(26+25\right)-18\)
\(=-51-18\)
\(=-\left(51+18\right)\)
\(=-69\)
c)\(35-\left(-19\right)-19-8\)
\(=35+19-19-8\)
\(=35+\left(19-19\right)-8\)
\(=35+0-8\)
\(=35-8\)
\(=27\)
d)\(1963-\left(-180\right)-1990\)
\(=1963+180-1990\)
\(=2143-1990\)
\(=153\)
2)Tìm x thuộc z biết
a)\(x-\left(-18\right)=25+\left(-17\right)\)
\(\Leftrightarrow x+18=25-17\)
\(\Leftrightarrow x+18=8\)
\(\Leftrightarrow x=8-18\)
\(\Leftrightarrow x=-10\)
Vậy x=-10
b)\(x-28=-27-30\)
\(\Leftrightarrow x-28=-\left(27+30\right)\)
\(\Leftrightarrow x-28=-57\)
\(\Leftrightarrow x=-57+28\)
\(\Leftrightarrow x=-\left(57-28\right)\)
\(\Leftrightarrow x=-29\)
Vậy x=-29
c)\(35-\left(-x\right)=27-18-\left(-8\right)\)
\(\Leftrightarrow35+x=27-18+8\)
\(\Leftrightarrow35+x=9+8\)
\(\Leftrightarrow35+x=17\)
\(\Leftrightarrow x=17-35\)
\(\Leftrightarrow x=-18\)
Vậy x=-18
d)\(40+\left(-x\right)=35-\left(-27\right)\)
\(\Leftrightarrow40-x=35+27\)
\(\Leftrightarrow40-x=62\)
\(\Leftrightarrow x=40-62\)
\(\Leftrightarrow x=-22\)
Vậy x=-22
a ) x - ( - 18 ) = -24
x + 18 = -24
x = -24 - 18
x = -6
b ) -x - 17 + 8 = 33 - 19
-x - 17 + 8 = 14
-x - 17 = 14 - 8
-x - 17 = 6
-x = -( 6 + 17 )
-x = - 23
c ) 15 - ( -4 + 7 ) = x - 14
15 + 4 + 7 = x - 14
27 = x - 14
x - 14 = 27
x = 27 + 14
x = 41
d ) 9 - 25 = ( 7 - x ) - ( 25 + 7 )
( 7 - x ) - 32 = -16
7 - x = -16 + 32
-7 - x = -16
x = -7 - ( - 16)
x = -7 + 16
x = 9
a) x + 118 = 218
x = 218 – 118
x = 100
b) 18 – x = -17
X = 18 – (-17)
X = 35
c) (-18) – x = -17
X = (-18) – (-17)
X = -1
d)124 + (118 – x) = 217
118 – x = 93
X = 118 – 93
X = 25
e) (3x – 6).3 = 34
(3x – 6).3 = 81
3x – 6 = 27
3x = 33
ð X = 11
g) 23.(42 – x) = 46
42 – x = 2
ð X = 40
h) 84 – (3x + 8) = 34
3x + 8 = 84 – 34
3x + 8 = 50
3x = 50 – 8
3x = 42
X = 42 : 3
ð X = 14
i) 3.(2x + 1) – 19 = 14
3.(2x + 1) = 14 + 19
3.(2x + 1) = 33
2x + 1 = 33 : 3
2x + 1 = 11
2x = 11 – 1
2x = 10
X = 10 : 2
ð X = 5
k) 6x – 302 = 23.5
6x – 302 = 40
6x = 40 + 302
6x = 342
X = 342 : 6
ð X = 57
m) (x – 1)2 = 81
(x – 1)2 = 92
ð X – 1 = 9
ð X = 9 + 1
ð X = 10
n) 2x+1 – 5 = 27
2x+1 = 27 + 5
2x+1 = 32
2x+1 = 25
ð X = 4
1. THực hiện phép tính :
a) 17 - 25 + 55 - 17
= ( 17 - 17 ) + ( -25 + 55 )
= 0 + 30 = 30
b) 25 - (-75) + 32 - (32 + 75)
= 25 + 75 + 32 - 32 - 75
= 25 + ( 75 - 75 ) + ( 32 - 32 )
= 25 + 0 + 0 = 25
c) (-5).8.(-2).3
= [(-5).(-2)].(8.3)
= 10 . 24 = 240
d) (-15) + (- 122) = - ( 15 + 122 ) = -137
e) /-127/ - 18.(5-6)
= 127 - 18.(-1)
= 127 - ( -18 ) = 127 + 18 = 145
Trả lời
1.Thực hiện phép tính :
a)17-25+55-17
=(17-17)-25+55
=0-25+55
=30
b)25-(-75)+32-(32+75)
=25+75+32-32-75
=25+(75-75)+(32-32)
=25+0+0
=25
c)(-5).8.(-2).3
=[(-5).(-2)].3.8
=10.24
=240
d)(-15)+(-122)
=(-137)
e)|-127|-18.(5-6)
=127-18.(-1)
=127.(-18)
=(-2286)
Bài 2:
a)Ư (-8)={-1;-2;-4;-8}
b)B (-11)={-11;-22;-33;-44;-55}
Bài 3:
a)-13+x=39
=>x=39+13
=>x=52
b)3x-(-17)=14
3x+17 =14
3x =14-17
3x =(-3)
x =(-3):3
x =(-1)
c)|x+9|.2=10
|x+9| =10:2
|x+9| =5
|x| =5-9
|x| =-4
Vậy: x=4 hoặc -4
d)
12=22.3
10=2.5
BCNN (12;10)=22.3.5=60
BC (12;10) = {60;120;180}
Vậy x có thể là 1 trong 3 số trên: 60;120;180.
Đáp án cần chọn là: A
x+17=8
x=8–17
x=−9