BK
2
K
Khách
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TT
3
LH
7 tháng 12 2015
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
\(\Leftrightarrow4\text{x}+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}=1\)
\(\Leftrightarrow4\text{x}+\frac{15}{16}=1\)
\(\Leftrightarrow4\text{x}=1-\frac{15}{16}\)
\(\Leftrightarrow4\text{x}=\frac{1}{16}\)
\(\Leftrightarrow x=\frac{1}{16}:4=\frac{1}{64}\)
7 tháng 12 2015
(x+1/2)+(x+1/4)+(x+1/8)+(x+16)=1
(x.x.x.x)+(1/2+1/4+1/8+1/16=1
4x+(1/2+1/4+1/8+1/16)=1
4x+(8/16+4/16+2/16+1/16)=1
4x+15/16=1
4x=1-15/16
4x=1/16
x=1/16:4
=>x=1/64
tick cho mk nha bạn
T
6
15 tháng 7 2015
ta có:(x+x+x+x)+(1/2+1/4+1/8+1/16)=1 4x+15/16=1 4x=1-15/16 4x=1/16 x=1/16:4=1/64 vậy x=1/64 Mình trả lời trước nhé
N
15 tháng 7 2015
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
\(x+\frac{1}{2}+x+\frac{1}{4}+x+\frac{1}{8}+x+\frac{1}{16}=1\)
\(\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
\(4x+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
Đặt \(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\)
\(A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4}\)
\(2A=1+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}\)
\(A=1-\frac{1}{2^4}\)
\(A=\frac{15}{16}\)
Thay A vào đẳng thức ta có
\(4x+\frac{15}{16}=1\)
\(4x=1-\frac{15}{16}\)
\(4x=\frac{1}{16}\)
\(x=\frac{1}{16}\div4\)
\(x=\frac{1}{64}\)
KT
2
28 tháng 3 2017
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=\frac{23}{16}\)
\(\Leftrightarrow4x+\frac{15}{16}=\frac{23}{16}\)(Phá các dấu ngoặc)
\(\Leftrightarrow4x=\frac{23}{16}-\frac{15}{16}\)
\(\Leftrightarrow4x=\frac{1}{2}\left(=\frac{8}{16}\right)\)
\(\Leftrightarrow x=\frac{1}{2}:4\Leftrightarrow x=\frac{1}{8}\)
LA
28 tháng 3 2017
(x + 1/2)+(x+1/4)+(x+1/8)+(x +1/16)=23/26
=(x+8/16)+(x+4/16)+(x+2/16)+(x+1/16)=23/16
=4 nhân x +(8/16 + 4/16 + 2/16 + 1/16)=23/16
4 nhân x =23/16-15/16
4 nhân x=8/16
x=8/16 :4=1/8
Vậy x = 1/8
TK
2
MH
31 tháng 12 2015
\(\Rightarrow x+\frac{1}{2}+x+\frac{1}{4}+x+\frac{1}{8}+x+\frac{1}{16}=1\)
\(\Rightarrow4\times x+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
\(\Rightarrow4\times x+\frac{8+4+2+1}{16}=1\)
\(\Rightarrow4\times x+\frac{15}{16}=1\)
\(\Rightarrow4\times x=1-\frac{15}{16}=\frac{1}{16}\)
\(\Rightarrow x=\frac{1}{16}:4=\frac{1}{16}\times\frac{1}{4}\)
\(\Rightarrow x=\frac{1}{64}\).
8 tháng 3 2016
(x+1/2)+(x+1/4)+(x+1/8)+(x+1/16)=1
4x+(1/2+1/4+1/8+1/16)=1
4x+15/16=1
4x=1-15/16
4x=1/16
x=1/64
DK
2
7 tháng 11 2016
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)
\(4x+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)
\(4x+\frac{15}{16}=1\)
\(4x=1-\frac{15}{16}\)
\(4x=\frac{1}{16}\)
\(x=\frac{1}{16}:4\)
\(x=\frac{1}{64}\)
TL
0
FF
2
HS
1
Trả lời
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=\frac{23}{16}\)
\(\Leftrightarrow\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=\frac{23}{16}\)
\(\Leftrightarrow4x+\left(\frac{8}{16}+\frac{4}{16}+\frac{2}{16}+\frac{1}{16}\right)=\frac{23}{16}\)
\(\Leftrightarrow4x+\frac{8+4+2+1}{16}=\frac{23}{16}\)
\(\Leftrightarrow4x+\frac{15}{16}=\frac{23}{16}\)
\(\Leftrightarrow4x=\frac{23}{16}-\frac{15}{16}\)
\(\Leftrightarrow4x=\frac{8}{16}\)
\(\Leftrightarrow4x=\frac{1}{2}\)
\(\Leftrightarrow x=\frac{1}{2}:4\)
\(\Leftrightarrow x=\frac{1}{8}\)
Vậy x=\(\frac{1}{8}\)
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=\frac{23}{16}\)
\(\Leftrightarrow\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=\frac{23}{16}\)
\(\Leftrightarrow4x+\left(\frac{8+4+2+1}{16}\right)=\frac{23}{16}\)
\(\Leftrightarrow4x+\frac{15}{16}=\frac{23}{16}\)
\(\Leftrightarrow4x=\frac{23}{16}-\frac{15}{16}\)
\(\Leftrightarrow4x=\frac{1}{2}\)
\(\Leftrightarrow x=\frac{1}{2}:4\)
\(\Leftrightarrow x=\frac{1}{8}\)