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Mình dùng dấu . thay cho dấu nhân nha
a) \(x.45+x.55=100\)
\(\Rightarrow x\left(45+55\right)=100\)
\(\Rightarrow x.100=100\Rightarrow x=1\)
b) \(\frac{6}{x}+\frac{1}{2}=2\)
\(\Rightarrow\frac{6}{x}=2-\frac{1}{2}\)
\(\Rightarrow\frac{6}{x}=\frac{5}{2}\)
\(\Rightarrow5.x=2.6=12\)
\(\Rightarrow x=\frac{12}{5}\)
\(a,x\times45+x\times55=100\)
\(x\times\left(45+55\right)=100\)
\(x\times100=100\)
\(x=100\div100\)
\(x=1\)
\(b,\frac{6}{x}+\frac{1}{2}=2\)
\(\frac{6}{x}=2-\frac{1}{2}\)
\(\frac{6}{x}=\frac{3}{2}\)
\(\frac{6}{x}=\frac{6}{4}\)
\(x=4\)
x . 45 + x . 55 = 1000
x . ( 45 + 55 ) = 1000
x . 100 = 1000
x = 1000 : 100
x = 10
Vậy x = 10
6 / x + 1 / 2 = 2
6 / x = 2 - 1 / 2
6 / x = 3 / 2
6 / x = 6 / 4
=> x = 4
Vậy x = 4
a, X x 45 + X x 55 = 1000
X x (45 + 55) = 1000
X x 100 = 1000
X = 1000 : 100
X = 10
b, \(\frac{6}{x}+\frac{1}{2}=2\)
\(\frac{6}{x}=2-\frac{1}{2}\)
\(\frac{6}{x}=\frac{3}{2}\)
\(\frac{6}{x}=\frac{6}{4}\)
\(x=4\)
a ) \(x\times45+x\times55=1000\)
\(x\times\left(45+55\right)=1000\)
\(x\times100=1000\)
\(x=1000\div100=10\)
b ) \(\frac{6}{x}+\frac{1}{2}=2\)
\(\frac{6}{x}=2-\frac{1}{2}\)
\(\frac{6}{x}=\frac{3}{2}\)
\(=>x=6\div3\times2=4\)
Bài 1:
\(A=\frac{1}{\left(1+2\right)}+\frac{1}{\left(1+2+3\right)}+\frac{1}{\left(1+2+3+4\right)}\)\(+\frac{1}{\left(1+2+3+4+5\right)}+...+\)\(\frac{1}{\left(1+2+3+...+10\right)}\)
\(A=\frac{1}{3}+\frac{1}{6}+....+\frac{1}{55}\)
\(A=2\left(\frac{1}{6}+\frac{1}{12}+....+\frac{1}{110}\right)\)
\(A=2\left(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{10.11}\right)\)
\(A=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{10}-\frac{1}{11}\right)\)
\(A=2.\left(\frac{1}{2}-\frac{1}{11}\right)\)
\(A=\frac{9}{11}\)
Bài 2 :
2) Tử số = 11 x 13 x 15 + 3 x 3 x 3 x 11 x 13 x 15 + 5 x 5 x 5 x 11 x 13 x 15 + 9 x 9 x 9 x 11 x 13 x 15
= (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) x 11 x 13 x 15 = (1+27+125+ 729) x 11 x 13 x 15
Mẫu số = 11 x 13 x 17 + 3 x 3 x 3 x 13 x 15 x 19 + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17 lớn hơn 11 x 13 x 15 + 3 x 3 x 3 x 13 x 15 x 17 + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17
= (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) 13 x 15 x 17 = (1+27+125+729) x 13 x 15 x 17
\(\Rightarrow A< \frac{\left(1+27+125+729\right)\times11\times13\times15}{\left(1+27+125+729\right)\times13\times15\times17}\)
\(=\frac{11}{17}\)
\(=\frac{1111}{1717}=B\)
Vậy \(A=B\)
a: =>x(34,5+66,5-1)=1000
=>100x=1000
=>x=10
b: =>x*473,4=3787,2
=>x=8
c: =>136,5-x=4,5
=>x=132
d: =>x(34,56-25,56+1)=0,1
=>10x=0,1
=>x=0,01
a. x x 45 + x x 55 = 1000
x x (45 + 55) = 1000
x x 100 = 1000
x = 1000 : 100
x = 10
b.
6 x + 1 2 = 2 6 : x + 1 2 = 2 6 : x = 2 - 1 2 6 : x = 3 2 x = 6 : 3 2 x = 4