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(2,5x - 4/3)2 - 5/6 = -7/18
=> (2,5x - 4/3)2 = -7/18 + 5/6
=> (2,5x - 4/3)2 = 4/9
=> (2,5x - 4/3)2 = (2/3)2
=> \(\orbr{\begin{cases}2,5x-\frac{4}{3}=\frac{2}{3}\\2,5x-\frac{4}{3}=-\frac{2}{3}\end{cases}}\)
=> \(\orbr{\begin{cases}x=\frac{4}{5}\\x=\frac{4}{15}\end{cases}}\)
\(\left(2,5x-\frac{4}{3}\right)^2-\frac{5}{6}=-\frac{7}{18}\)
\(\left(2,5x-\frac{4}{3}\right)^2=-\frac{7}{18}+\frac{5}{6}\)
\(\left(2,5x-\frac{4}{3}\right)^2=\frac{4}{9}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{4}{5}\\x=\frac{4}{15}\end{cases}}\)
Ta có \(\frac{3}{2}-\frac{5}{2}.\left(1,2x-3\right)^2=-0,9\)
\(\Rightarrow\frac{5}{2}.\left(1,2x-3\right)^2=\frac{3}{2}+0,9\)
\(\Rightarrow\frac{5}{2}.\left(1,2x-3\right)^2=\frac{21}{2}\)
\(\Rightarrow\left(1,2x-3\right)^2=\frac{21}{5}\)
đề sai hay mình sai ????
b/ \(\left|\left|3x-1+9\right|\right|=-\left(-31\right)\)
<=> \(\left|\left|3x+8\right|\right|=31\)
<=> \(\left|3x+8\right|=31\)
<=> \(\orbr{\begin{cases}3x+8=-31\\3x+8=31\end{cases}}\)
<=> \(\orbr{\begin{cases}3x=-39\\3x=23\end{cases}}\)
<=> \(\orbr{\begin{cases}x=-13\\x=\frac{23}{3}\end{cases}}\)
Ax1000 = 1830.11/5 - 672.22 -110.11/5 +1000
=(1830.11 -672.22.5-110.11+5000)/5
=(1830.11-6720.11-110.11+5000)/5=(1830.11-6830.11+5000)/5=(-5000.11+5000 )/5=-5000.10/5=-1000.10
vậy A = -10
\(\left(\frac{-3}{2x}+\frac{1}{4}\right):\frac{1}{6}=\frac{-3}{2}\)
\(\Rightarrow\frac{-3}{2x}+\frac{1}{4}=\frac{-3}{2}.\frac{1}{6}=-\frac{1}{4}\)
\(\Rightarrow\frac{-3}{2x}=-\frac{1}{4}-\frac{1}{4}=-\frac{1}{2}\)
\(\Rightarrow\frac{-3}{2x}=\frac{-3}{6}\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
(-3/2x + 0,25) : 1/6 = -3/2
=> -3/2x + 0,25 = -3/2 . 1/6
=> -3/2x + 0,25 = -1/4
=> -3/2x = -1/4 - 0,25
=> -3,2x = -1/2
=> x = -1/2 : (-3/2)
=> x = 1/3