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1) 9-25=(7-x)-(25+7)
(7-x)-(25+7)=9-25
(7-x)-(25+7)=-16
(7-x)-32=-16
7-x=-16+32
7-x=16
x=7-16
x=-9
2) (27-514) -(486-73)+x=7
(27-514) -(486-73)+x=7
-487-413+x=7
-1011+x=7
x=7-(-1011)
x=7+1011
x=1018
3) 25+5+37-25+6-29-x=37
25+5+37-25+6-29-x=37
67-25+6-29-x=37
42+6-29-x=37
48-29-x=37
19-x=37
x=19-37
x=-18
4) 14+(-12)+x =10-/-15/+ /-3/
14+(-12)+x =10-15+3
14+(-12)+x =-5+3
14+(-12)+x =-2
2+x=-2
x=-2-2
x=-4
Bài 1:
a) 17-25+55-17
=(17-17)+(-25+55)
=0+30
=30
b.(-37+101)-(91+37)
= -37+101-91-37
=(-37-37)+(101-91)
= -74 + 10
=-64
c.(-4-6):(-5)
=(-10) : (-5)
=2
d)35-(-95)+372-(372+95)
=35+95+372-372-95
=35+(95-95) + ( 372-372)
=35
a) \(\left(2x-1\right)^2-25=0\)
\(\left(2x-1\right)^2=0+25=25\)
\(\left(2x-1\right)^2=5^2=\left(-5\right)^2\)
\(\Rightarrow\left[\begin{array}{nghiempt}2x-1=5\\2x-1=-5\end{array}\right.\Rightarrow\left[\begin{array}{nghiempt}2x=6\\2x=-4\end{array}\right.\Rightarrow\left[\begin{array}{nghiempt}x=3\\x=-2\end{array}\right.\)
b) \(8x^3-50x=0\)
\(2x\left(4x^2-25\right)=0\)
\(\Rightarrow\left[\begin{array}{nghiempt}2x=0\\4x^2-25=0\end{array}\right.\Rightarrow\left[\begin{array}{nghiempt}x=0\\4x^2=25\Rightarrow x^2=\frac{25}{4}\Rightarrow\left[\begin{array}{nghiempt}x=\frac{5}{2}\\x=-\frac{5}{2}\end{array}\right.\end{array}\right.\)
\(a,5x-16=40-1\)
<=>\(5x=40-1+16\)
<=>\(5x=55\)
<=>\(x=11\)
\(b,x-10=-25\)
<=>\(x=\left(-25\right)-10\)
<=>\(x=-35\)
\(c,-12+x=-30\)
<=>\(x=\left(-30\right)+12\)
<=>\(x=-18\)
a) 5x-16=40-1
5x-16=39
5x=39+16
5x=55
x=55:5
x=11
b)x-10=(-25)
x=(-25)+10
x=(-15)
c) -12+x= -30
x= -30-(-12)
x= -30+12
x= -18
d) 2x +12 = -40+ 6
2x+12=(-34)
2x=(-34)-12
2x=(-46)
x=(-46):2
x=(-23)
e)125:(3x-13)=25
3x-13=125:25
3x-13=5
3x=5+13
3x=18
x=18:3
x=6
f)541+(218-x)=735
218-x=735-541
218-x=194
x=218-194
x= 24
g) 3(2x+1)-19=14
3(2x+1)=14+19
3(2x+1)=33
2x+1=33:3
2x+1=11
2x=11-1
2x=10
x=10:2
x=5
h)175-5(x+3)=85
5(x+3)=175-85
5(x+3)=90
x+3=90:5
x+3=18
x=18-3
x=15
i)8x+(-3)=39
8x=39-(-3)
8x=42
x=42:8
x=42/8
L)2x+4x=36+(-6)
6x=30
x=30:6
x=5
a)-2x - 3.(x - 17) = 34 - (-x + 25)
- 2x - 3x + 51 = 34 + x - 25
- 2x - 3x - x = -51 + 34 - 25
- 6x = - 42
x = 7
Vậy x = 7
b)-2x-3.(x-17)=34-2(-x+25)
- 2x - 3x + 51 = 34 + 2x - 50
- 2x - 3x - 2x = - 51 + 34 - 50
7x = - 67
x = \(-\frac{67}{7}\)
Vậy \(x=-\frac{67}{7}\)
c)17x-(-16x-37)=2x +43
17x + 16x + 37 = 2x + 43
17x + 16x - 2x = -37 + 43
31x = 6
x = \(\frac{6}{31}\)
Vậy \(x=\frac{6}{31}\)
\(25\cdot x^2=25\\ x^2=25\div25\\ x^2=1\\ x^2=1^2\\ x=1\\ 8^{x-3}=1\\ 8^{x-3}=8^0\\ x-3=0\\ x=0+3\\ x=3\)
`@` `\text {Ans}`
`\downarrow`
\(3^{x+6}=37\)
`=>`\(3^x\cdot3^6=37\)
`=>`\(3^x=37\div3^6\)
`=>` \(3^x=\dfrac{37}{729}\)
Bạn xem lại đề.
\(25x^2=25\)
`=>`\(x^2=25\div25\)
`=>`\(x^2=1\)
`=> x=1`
\(8^{x-3}=1\)
`=>`\(8^x\div8^3=1\)
`=>`\(8^x=8^3\)
`=> x=3`