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1. x + 2x = -36
=> 3x = -36
=> x = -36 : 3
=> x = -12
2. (2x + 3) \(⋮\)(x - 2)
=> (2x - 2) + 5 \(⋮\)(x - 2)
=> 2(x - 2) + 5 \(⋮\)(x - 2)
=> 5 \(⋮\)(x - 2)
=> x - 2 \(\in\)Ư(5) = {-5;-1;1;5}
=> x \(\in\){-3;1;3;7}
3. Khi đó a . (-b) = -132
4. -2(3x + 2) = 12 + 22 + 32
=> -2(3x + 2) = 1 + 4 + 9
=> -2(3x + 2) = 14
=> 3x + 2 = 14 : (-2)
=> 3x+ 2 = -7
=> 3x = -7 - 2
=> 3x = -9
=> x = -9 : 3
=> x = -3
1/ \(x+2x=-36\)
\(\Rightarrow3x=-36\)
\(\Rightarrow x=-\frac{36}{3}\)
\(\Rightarrow x=-12\)
2/ \(\left(2x+3\right)⋮\left(x-2\right)\)
\(\Leftrightarrow\left(2x-4\right)+7⋮\left(x-2\right)\)
\(\Leftrightarrow2\left(x-2\right)+7⋮\left(x-2\right)\)
\(\Rightarrow7⋮\left(x-2\right)\)
\(\Rightarrow\left(x-2\right)\inƯ\left(7\right)\)
\(\Rightarrow x\inƯ\left(7-2\right)\)
\(\Rightarrow x\inƯ\left(5\right)\)
\(\Rightarrow x\in\left\{-5,1,5\right\}\)
Vậy x nhỏ nhất để \(\left(2x-3\right)⋮\left(x-2\right)\) là -5
3/ Vì \(a\cdot b=32\)
\(\Rightarrow-a\cdot b=-\left(a\cdot b\right)=-32\)
4/ \(-2\left(3x+2\right)=1^2+2^2+3^2\)
\(\Leftrightarrow-6x-4=1+4+9\)
\(\Leftrightarrow-6x=14+4\)
\(\Leftrightarrow-6x=18\)
\(\Leftrightarrow x=\frac{18}{-6}\)
\(\Rightarrow x=3\)
a) (x: 8 - l).2 = 1.14 nên x : 8 - 1 = 7. Do đó x = 64.
b) (2x + 3).30 = 25.6 nên 2x + 3 = 5. Do đó x = 1.
c) 6.(2x - 7) = 9.(x - 3) nên 12x - 42 = 9x - 27.
Do đó 3x = 15. Vậy x = 5.
d) -7.(x + 27) = 6.(x + l) nên -7x - 189 = 6x + 6.
Do đó 13x = -195. Vậy x = -15.
1,\(54.\left(23-11\right)+23.\left(-22-54\right)\)
\(=54.12+23.\left(-76\right)\)
\(=648-1748\)
\(=-1100\)
2,\(-7+2x=-17-\left(-36\right)\)
\(=>-7+2x=-17+36\)
\(=>-7+2x=19\)
\(=>2x=19+7=26\)
\(=>x=\frac{26}{2}=13\)
3,\(5⋮2a+3\)
\(=>2a+3\inƯ\left(5\right)\)
\(=>2a+3\in\left\{-1;-5;1;5\right\}\)
\(=>2a\in\left\{-4;-8;-2;2\right\}\)
\(=>a\in\left\{-2;-4;-1;1\right\}\)
Vậy ...
54 . ( 23 - 11 ) + 23 . ( -22 - 54 )
=54.23-54.11+23.-22-23.54
=-54.11+23.-22
=-22(27+23)
=-22.50
=-1100
-7 + 2x = -17 - ( -36 )
-7+2x=-17+36
-7+2x+17-36=0
-26+2x=0
2x=26
x=13
Vậy x=13
Để \(5⋮\left(2a+3\right)\Leftrightarrow\left(2a+3\right)\inƯ\left(5\right)\)
\(\Leftrightarrow\left(2a+3\right)\in\left\{\pm1;\pm5\right\}\)
\(\Leftrightarrow a\in\left\{-1;-2;1;-4\right\}\)
x.(1 + 2) = -36
x.3= -36
x = -36:3
x= -12
-12 nha minh lam roi
tk nha