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Bài 2:
a: =>x=0 hoặc x+3=0
=>x=0 hoặc x=-3
b: =>x-2=0 hoặc 5-x=0
=>x=2 hoặc x=5
c: =>x-1=0
hay x=1
a) (2x - 3)(6 - 2x) = 0
=> \(\left[{}\begin{matrix}2x-3=0\\6-2x=0\end{matrix}\right.=>\left[{}\begin{matrix}2x=3\\2x=6\end{matrix}\right.=>\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=3\end{matrix}\right.\)
b) \(5\dfrac{4}{7}:x=13=>\dfrac{39}{7}:x=13=>x=\dfrac{39}{7}:13=>x=\dfrac{3}{7}\)
c) \(2x-\dfrac{3}{7}=6\dfrac{2}{7}=>2x-\dfrac{3}{7}=\dfrac{44}{7}=>2x=\dfrac{47}{7}=>x=\dfrac{47}{14}\)
d) \(\dfrac{x}{5}+\dfrac{1}{2}=\dfrac{6}{10}=>\dfrac{x}{5}=\dfrac{6}{10}-\dfrac{1}{2}=>\dfrac{x}{5}=\dfrac{1}{10}=>x.10=5=>x=\dfrac{1}{2}\)
e) \(\dfrac{x+3}{15}=\dfrac{1}{3}=>\left(x+3\right).3=15=>x+3=5=>x=2\)
\(\frac{3}{x-5}=-\frac{4}{x+2}\)
=> 3 ( x + 2 ) = 4 ( x - 5 )
=> 3x + 6 = 4x - 20
=> 3x - 4x = - 6 - 20
=> - 1x = - 26
=> x = 26
1) 3/x-5=-4/x+2
3x+6=-4x+20
7x . =14
x . =2
2) x+3/-4=-9/x+3
(x+3)^2=36
Ta có hai trường hợp:
*x+3=6=)x=3
*x+3=-6=)x=-9
a. 2x+\(\dfrac{4}{5}\)=0 hoặc 3x-\(\dfrac{1}{2}\)=0
2x=- 4/5 hoặc 3x=1/2
x=-2/5 hoặc x=\(\dfrac{1}{6}\)
b. x-\(\dfrac{2}{5}\)=0 hoặc x+\(\dfrac{4}{7}\)=0
x=2/5 hoặc x=-\(\dfrac{4}{7}\)
d. x(1+5/8-12/16)=1
\(\dfrac{7}{8}\)x=1=> x=8/7
1) 2(x - 5) - 3(x + 7) = 14
2x - 10 - 3x - 21 = 14
2x - 3x = 14 + 21 + 10
- x = 45
x = -45
2) 5(x - 6) - 2(x + 3) = 12
5x - 30 - 2x - 6 = 12
3x = 12+ 30 + 6
3x = 48
x = 16
3) -7(5 - x) - 2(x - 10) = 15
-35 + 7x - 2x + 20 = 15
5x = 15 - 20 + 35
5x = 30
x = 6
4) 3(x - 4) - (8 - x) = 12
3x - 12 - 8 + x =12
4x = 12 + 8 + 12
4x = 32
x = 8
5) 4(x - 5) - 3(x + 7) = -19
4x - 20 - 3x - 21 = -19
x = -19 + 21 + 20
x = 22
6) 7(x - 3) - 5(3 - x) = 11x - 5
7x - 21 - 15 + 5x = 11x - 5
7x + 5x - 11x = -5 + 21 + 15
x = 31
7) 4(2 - x) + 3(x - 5) = 14
8 - 4x + 3x - 15 = 14
- x = 14 + 15 - 8
- x = 21
x = -21
