Question

[Thượng Hoàng Yến]

tim so huu ti x biet

\(\frac{x}{y^2}\)=2 va \(\frac{x}{y}\)=16  (voi y khac 0)

\(\frac{1+2y}{18}\)=\(\frac{1+4y}{24}\)=\(\frac{1+6y}{6x}\)

Answer 1

[Nguyễn Anh Quân]

a, => (x^2/y):(x/y) = 2:16 

=> 1/y = 1/8 => y=8 ; x = 128

b, 1+2y/18 = 1+4y/24

<=> (1+2y).24 = (1+4y).18

<=> 24+48y = 18+72y

<=> 72y+18-24-48y=0

<=>24y-6=0

<=> 24y=6

<=> y=6:24 = 1/4

Khi đó : 1+2y/18 = 1+6y/6x

<=> 1+1/2/18 = 1+3/2 / 6x

<=> 1/12 = 5/12x

<=> 12x = 5: 1/12 = 60

<=> x = 60:12 = 5

Vậy .......

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