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a) 27 . 75 + 25 . 27 - 150 = 2025 + 675 - 150 = 2700 - 150 = 2550.
Lưu ý. Có thể dùng tính chất phân phối của phép nhân đối với phép cộng để nhẩm:
27 . 75 + 25 . 27 - 150 = 27 . (75 + 25) - 150 = 27 . 100 - 150 = 2700 - 150 = 2550.
b) 12 : {390 : [500 - (125 + 35 . 7)]} = 12 : {390 : [500 - (125 + 245)]}
= 12 : [390 : (500 - 370)] = 12 : (390 : 130) = 12 : 3 = 4.
a,27+75.25+27-150
= 27.(75+25)-150
=27.100-150
=2700-150
=2550
b,12:{390:[500-(125+35.7)]}
=12:{390:[500-(125+245)]}
=12:{390:[500-370]}
=12:{390:130}
=12:3
=4
Thank you very much
a, = 27 . ( 75 + 25 ) - 150
= 27 . 100 - 150
= 2700 - 150
= 2550
b, = 12 : { 390 : [ 500 - 370 ]
= 12 : { 390 : 130 }
= 12 : 3
= 4
a) 27.75+25.27-150=2025+675-150
=2700-150
=2550
b) 12:{390:[500-(125+35.7)]}=12:{390:[500-(125+245)]}
=12:[390:(500-370)]
=12:(390:130)
=12:3
=4
a) \(27\cdot75+25\cdot27-150\)
\(=27\cdot\left(75+25\right)-150\)
\(=27\cdot100-150\)
\(=2700-150\)
\(=2550\)
b) \(12:\left\{390:\left|500-\left(125+35\cdot7\right)\right|\right\}\)
\(=12:\left\{390:\left|500-\left(125+245\right)\right|\right\}\)
\(=12:\left\{390:\left|500-370\right|\right\}\)
\(=12:\left\{390:130\right\}\)
\(=12:3\)
\(=3\)
a)27.75+25.27-150
=27.(75+25)-150
=27.100-150
=2700-150
=2550
\(a,27.75+25.27-150\)
\(=27.\left(75+25\right)-150\)
\(=27.100-150\)
\(=2700-150\)
\(=2550\)
\(b,12:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}\)
\(=12:\left\{390:\left[500-\left(125+245\right)\right]\right\}\)
\(=12:\left[390:\left(500-370\right)\right]\)
\(=12:\left(390:130\right)\)
\(=12:3\)
\(=4\)
a) 27.75+25.27-150
= 27.(75+25)-150
= 27.100-150
= 2550
b) 12:{390:[500-(125+75.7)]}
= 12:{390:(500-25.26)}
= 12:{390:[25.(20-26)]}
= 12:(390:(-150)]}
= 12 : \(\dfrac{-13}{5}\)
= \(\dfrac{-60}{13}\)
a)27.75+25.27-150=27.(75+25)-150=27.100-150=2700-150=26850
b)\(12:\left\{390:\left[500-\left(25.5+25.3.7\right)\right]\right\}\)
\(=12:\left\{390:\left[25.20-25.26\right]\right\}\)
\(=12:\left\{3.10.13:\left[-25.6\right]\right\}\)
\(=12:\left(\dfrac{-13}{5}\right)=-12.\dfrac{5}{13}=\dfrac{-60}{13}\)
\(a.25.\left(75+25\right)-150.\)
\(=25.100-150\)
\(=2500-150=2350\)
\(b.12:\left\{390:\left[500-\left(125+245\right)\right]\right\}\)
\(=12\left\{390:\left[500-370\right]\right\}\)
\(=12:\left\{390:130\right\}\)
\(=12:3=4\)
a) 27 . 75 + 25 . 27 - 150
= 27 . ( 75 + 25 ) - 150
= 27 . 100 - 150
= 2700 - 150
= 2550
b) 12 : {390 : [500 - (125 + 35 . 7)]}.
= 12 : {390 : [500 - (125 + 245 ) ] }
= 12 : {390 : [500 - 370 ] }
= 12 : {390 : 130 }
= 12 : 3
= 4
Bài 1: Thực hiện các phép tính sau:
\(a)\)Chưa rỏ đề
\(b)\)\(5025\div5-25\div5\)
\(=\)\(1005-5\)
\(=\)\(1000\)
\(c)\)\(218-180\div2\div9\)
\(=\)\(218-10\)
\(=\)\(208\)
\(d)\)\(\left(328-8\right)\div32\)
\(=\)\(320\div32\)
\(=\)\(10\)
Bài 1:
a) ( Tôi không nhìn rõ đầu bài )
b) 5025 : 5 - 25 : 5
= ( 5025 - 25 ) : 5
= 5000 : 5
= 1000
c) 218 - 180 : 2 : 9
= 218 - 180 : ( 2 . 9 )
= 218 - 180 : 18
= 218 - 10
= 208
d) ( 328 - 8 ) : 32
= 320 : 32
= 10
a, 25.(75 + 27 - 150 )
= 25 . (-48)
= - 1200
b, 12 : { 390 : [500 - 370 ]
= 12 : { 390 : 130 }
= 12 : 3
= 4
a) \(27.75+25.27-150\)
\(=27.\left(75+25\right)-150\)
\(=27.100-150\)
\(=2700-150\)
\(=2550\)
b) \(12:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}\)
\(=12:\left\{390:\left[500-370\right]\right\}\)
\(=12:\left\{390:130\right\}\)
\(=12:3\)
\(=4\)