Question

[Tuyết Ly]

Thực hiện các phép tính sau:

A = (x⁴-x²+ 2x -1) : (x²+ x -1) - (x²-x)

B = \(\dfrac{x+1}{x-2}+\dfrac{4}{x+2}+\dfrac{2-7x}{x^2-4}\)

Answer 1

[Lấp La Lấp Lánh]

1) \(A=\left[x^4-\left(x-1\right)^2\right]:\left(x^2+x-1\right)-x^2+x=\left[\left(x^2-x+1\right)\left(x^2+x-1\right)\right]:\left(x^2+x-1\right)-x^2+x=x^2-x+1-x^2+x=1\)

2) \(B=\dfrac{\left(x+1\right)\left(x+2\right)+4\left(x-2\right)+2-7x}{\left(x-2\right)\left(x+2\right)}=\dfrac{x^2-4}{x^2-4}=1\)

Answer 2

[snafkooz]

A= ( x^4-x^2-2x-1)