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333444=(3.111)4.111=(81.1114)111=(81.111.1113)111
444333=(4.111)3.111=(64.1113)111
Vì (81.111.1113)111>(64.1113)111 nên 333444>444333
a)\(333^{444}=3^{444}.111^{444}=\left(3^4\right)^{111}.111^{444}=81^{111}.111^{444}\)
\(444^{333}=4^{333}.111^{333}=\left(4^3\right)^{111}.111^{333}=64^{111}.111^{333}\)
Từ \(\hept{\begin{cases}81^{111}>64^{111}\\111^{444}>111^{333}\end{cases}}\Rightarrow81^{111}.111^{444}>64^{111}.111^{333}\Rightarrow333^{444}>444^{333}\)
b)\(5^{300}=\left(5^2\right)^{150}=25^{150};4^{453}=\left(4^3\right)^{151}=64^{151}\)
Vì 25150<64151 => 5300<4453
c)\(5^{217}>5^{216}=\left(5^3\right)^{72}=125^{72}>119^{72}\) => \(5^{217}>119^{72}\)
5\(^{300}\)=25\(^{150}\)
3\(^{453}\)=27\(^{151}\)=27.27\(^{150}\)
vì 25\(^{150}\)<27.27\(^{150}\)
\(\Rightarrow\)5\(^{300}\)<3\(^{453}\)
31\(^{11}\)<32\(^{11}\)=(2\(^5\))\(^{11}\)=2\(^{55}\)
31\(^{11}\)<2\(^{55}\)
17\(^{14}\)>16\(^{14}\)=2\(^{56}\)
31\(^{11}\)<2\(^{55}\)<2\(^{56}\)<17\(^{14}\)
\(\Rightarrow\)31\(^{11}\)<17\(^{14}\)
333\(^{444}\)=3\(^{444}\).111\(^{444}\)
444\(^{333}\)=4\(^{333}\).111\(^{333}\)
ta có 3\(^{444}\)=81\(^{111}\)
4\(^{333}\)=64\(^{111}\)
\(\Rightarrow\)3\(^{444}\)>4\(^{333}\)(81\(^{111}\)>64\(^{111}\))
111\(^{444}\)>111\(^{333}\)
3\(^{444}\).111\(^{444}\)>4\(^{333}\).111\(^{333}\)
Vậy 333\(^{444}\)>444\(^{333}\)
nảy mình làm thiếu 1 câu bây giờ bù nhá
1030= (103)10= 100010
2100=(210)10=102410
1000<1024 =>100010<102410 nên 1030<2100