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Ta có: \(\sqrt{x}-3,5=8,5\)
\(\Rightarrow\sqrt{x}=8,5+3,5\)
\(\Rightarrow\sqrt{x}=12\)
\(\Rightarrow x=144\)
Hoc tốt nha^^
3,5 + /x + \(\frac{3}{2}\) / = -1,5(-\(\sqrt{9}\))
=> 3,5 +/ x +\(\frac{3}{2}\) / = -1,5 ( -3 )
=> 3,5 + / x + \(\frac{3}{2}\) / =4,5
=> / x + \(\frac{3}{2}\) / = 4,5 - 3,5
=> / x + \(\frac{3}{2}\) / = 1
=> \(\hept{\begin{cases}x+\frac{3}{2}=1\\x+\frac{3}{2}=-1\end{cases}}\)
=> \(\hept{\begin{cases}x=1-\frac{3}{2}\\x=-1-\frac{3}{2}\end{cases}}\)
=> \(\hept{\begin{cases}x=\frac{-1}{2}\\x=\frac{-5}{2}\end{cases}}\)
vậy x = \(\frac{-1}{2}\)hay x = \(\frac{-5}{2}\)
\(3,5+\left|x+\frac{3}{2}\right|=-1,5.\left(-\sqrt{9}\right)\) \(3,5+\left|x+\frac{3}{2}\right|=-1,5.\left(-3\right)\) \(3,5+\left|x+\frac{3}{2}\right|=4,5\) \(\left|x+\frac{3}{2}\right|=4,5-3,5\) \(\left|x+\frac{3}{2}\right|=1\) \(\Rightarrow\orbr{\begin{cases}x+\frac{3}{2}=1\\x+\frac{3}{2}=-1\end{cases}}\) \(\Rightarrow\orbr{\begin{cases}x=-\frac{1}{2}\\x=-\frac{5}{2}\end{cases}}\) Vậy x=\(-\frac{1}{2}\) hoặc x=\(-\frac{5}{2}\)
\(3,5+\left|x+\dfrac{3}{2}\right|=-1,5\cdot\left(-\sqrt{9}\right)\)
\(3,5+\left|x+\dfrac{3}{2}\right|=-1,5\cdot\left(-3\right)\)
\(3,5+\left|x+\dfrac{3}{2}\right|=4,5\)
\(\left|x+\dfrac{3}{2}\right|=4,5-3,5\)
\(\left|x+\dfrac{3}{2}\right|=1\)
\(\Rightarrow x+\dfrac{3}{2}=1\) hoặc \(x+\dfrac{3}{2}=-1\)
\(x=1-\dfrac{3}{2}\) \(x=-1-\dfrac{3}{2}\)
\(x=\dfrac{-1}{2}\) \(x=\dfrac{-5}{2}\)
Vậy \(x=\dfrac{-1}{2}\)hoặc \(x=\dfrac{-5}{2}\)
\(3,5+\left|x+\dfrac{3}{2}\right|=-1,5.\left(-\sqrt{9}\right)\)
\(\Rightarrow3,5+\left|x+\dfrac{3}{2}\right|=4,5\)
\(\Rightarrow\left|x+\dfrac{3}{2}\right|=4,5-3,5=1\)
\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{3}{2}=1\\x+\dfrac{3}{2}=-1\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=1-\dfrac{3}{2}\\x=-1-\dfrac{3}{2}\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=\dfrac{-1}{2}\\x=\dfrac{-5}{2}\end{matrix}\right.\)
Vậy..................
\(=\dfrac{1}{16}-\dfrac{7}{2}+\sqrt{7}=\dfrac{-55}{16}+\sqrt{7}\)
\(\left(-\dfrac{1}{4}\right)^2-3,5+\sqrt{7}\\ =\dfrac{1}{16}-3,5+\sqrt{7}\\ =-\dfrac{55}{16}+\sqrt{7}\\ =\dfrac{-55+16\sqrt{7}}{16}\)
a: Trường hợp 1: x>=-2,3
A=2x+4,6-2x+15,4=20
Trường hợp 2: x<-2,3
M=-2x-4,6-2x+15,4=-4x+10,8
b: Trường hợp 1: x<-7,2
M=-x-7,2-(1,2-x)
=-x-7,2-1,2+x=-8,4
Trường hợp 2: -7,2<=x<1,2
B=x+7,2-(1,2-x)
=x+7,2-1,2+x=2x+6
Trường hợp 3: x>=1,2
B=x+7,2-x+1,2=8,4
c: Trường hợp 1: x>=-3
C=8,5x-19,5-(1,5x+4,5)
=8,5x-19,5-1,5x-4,5
=7x-24
Trường hợp 2: x<-3
C=8,5x-19,5-(-1,5x-4,5)
=8,5x-19,5+1,5x+4,5
=10x-15
A=/2x+4,6/-2x+15,4
TH1:/2x+4,6/> hoặc =4,6
/2x+4,6/-2x+15,4
=(2x+4,6)-2x+15,4
=2x+4,6-2x+15,4
=2x+2x-4,6+15,4
=4x-20
Mình làm thế không biết đúng hay sai