Question

[Red Brown]

So sánh\(\frac{2^{23}+1}{2^{25}+1}\) và \(\frac{2^{25}+1}{2^{27}+1}\)

Answer 1

[Le Thi Khanh Huyen]

Ta có:

\(A=\frac{2^{23}+1}{2^{25}+1}\Rightarrow2A=\frac{2^{25}+2}{2^{25}+1}=1+\frac{1}{2^{25}+1}\)

\(B=\frac{2^{25}+1}{2^{27}+1}\Rightarrow2B=\frac{2^{27}+2}{2^{27}+1}=1+\frac{1}{2^{27}+1}\)

\(\frac{1}{2^{25}+1}>\frac{1}{2^{27}+1}\Rightarrow2A>2B\Rightarrow A>B\)