Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(1-\dfrac{13}{19}=\dfrac{6}{19}\\ 1-\dfrac{47}{53}=\dfrac{6}{53}\\ \dfrac{6}{19}>\dfrac{6}{53}\Rightarrow\dfrac{13}{19}< \dfrac{47}{53}\)
a)\(12< 13;49>47\)
\(\Rightarrow\dfrac{12}{49}< \dfrac{13}{47}\)
b)\(\dfrac{64}{85}>\dfrac{43}{85}\Rightarrow\dfrac{64}{85}>\dfrac{1}{2}\)
\(\dfrac{17}{35}< \dfrac{17}{34}\Rightarrow\dfrac{17}{35}< \dfrac{1}{2}\)
\(\Rightarrow\dfrac{17}{35}< \dfrac{64}{85}\)
c) \(\dfrac{19}{31}>\dfrac{16}{31}\Rightarrow\dfrac{19}{31}>\dfrac{1}{2}\)
\(\dfrac{17}{35}< \dfrac{17}{34}\Rightarrow\dfrac{17}{35}< \dfrac{1}{2}\)
\(\Rightarrow\dfrac{17}{35}< \dfrac{19}{31}\)
d)
\(1-\dfrac{67}{77}=\dfrac{10}{77}\)
\(1-\dfrac{73}{83}=\dfrac{10}{83}\)
\(\dfrac{10}{77}>\dfrac{10}{83}\Rightarrow\dfrac{67}{77}< \dfrac{73}{83}\)
e)\(1-\dfrac{456}{461}=\dfrac{5}{461}\)
\(1-\dfrac{123}{128}=\dfrac{5}{128}\)
\(\dfrac{5}{461}< \dfrac{5}{128}\Rightarrow\dfrac{456}{461}>\dfrac{123}{128}\)
\(a,\dfrac{12}{49}< \dfrac{12}{47}< \dfrac{13}{47}\Rightarrow\dfrac{12}{49}< \dfrac{12}{47}\)
b, Ta có: \(\dfrac{17}{35}=\dfrac{51}{105}\)
\(\dfrac{64}{85}>\dfrac{64}{105}>\dfrac{51}{105}\Rightarrow\dfrac{64}{85}>\dfrac{51}{105}\) hay \(\dfrac{64}{85}>\dfrac{17}{85}\)
c,\(\dfrac{19}{31}>\dfrac{17}{31}>\dfrac{17}{35}\Rightarrow\dfrac{19}{31}>\dfrac{17}{35}\)
d, \(\dfrac{67}{77}+\dfrac{10}{77}=1\)
\(\dfrac{73}{83}+\dfrac{10}{83}=1\)
\(\dfrac{10}{77}>\dfrac{10}{83}\Rightarrow\dfrac{67}{77}< \dfrac{73}{83}\)
e, \(\dfrac{456}{461}+\dfrac{5}{461}=1\)
\(\dfrac{123}{128}+\dfrac{5}{128}=1\)
\(\dfrac{5}{461}< \dfrac{5}{128}\Rightarrow\dfrac{456}{461}>\dfrac{123}{128}\)
Sửa đề: \(D=\dfrac{\dfrac{12}{19}-12+\dfrac{12}{47}}{\dfrac{6}{19}-6+\dfrac{6}{47}}=\dfrac{12\left(\dfrac{1}{19}-1+\dfrac{1}{47}\right)}{6\left(\dfrac{1}{19}-1+\dfrac{1}{47}\right)}=2\)
=28/15*3/4-(104/195+1/4)*24/47-(1+4/13)
=7/5-2/5-1-4/13
=-4/13
quy đồng
lấy 36 làm mẫu số chung
-13 / 12 = -39/36
-19/18 = -38/36
mà đối với số dương số nào lớn hơn thì số đó bé hơn
vậy -39/36 <-38/36
=> -13 / 12 < -19/18 = -38/36
Giải:
\(\dfrac{-13}{12}=-1+\dfrac{-1}{12}\)
\(\dfrac{-19}{18}=-1+\dfrac{-1}{18}\)
Vì \(\dfrac{-1}{12}< \dfrac{-1}{18}\) nên \(\dfrac{-13}{12}< \dfrac{-19}{18}\)
Chúc bạn học tốt!
a: \(\dfrac{12}{49}< \dfrac{13}{49}< \dfrac{13}{47}\)
b: \(\dfrac{12}{47}>\dfrac{19}{47}>\dfrac{19}{77}\)
a/ so sánh bằng 12/47
b/ chưa tìm ra