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\(\frac{111}{115}\)= 1 - \(\frac{4}{115}\)
\(\frac{555}{559}\)= 1 - \(\frac{4}{559}\)
\(\frac{4}{115}\)> \(\frac{4}{559}\)
=> \(\frac{111}{115}\) < \(\frac{555}{559}\)
a) Ta có:
\(\frac{15}{301}>\frac{15}{300}=\frac{1}{20}\)
\(\frac{25}{499}< \frac{25}{500}=\frac{1}{20}\)
Vì \(\frac{1}{20}=\frac{1}{20}\) nên \(\frac{15}{301}>\frac{1}{20}>\frac{25}{499}\) hay \(\frac{15}{301}=\frac{25}{499}\)
Vậy \(\frac{15}{301}>\frac{25}{499}\)
Ta có : \(-\frac{92}{111}< -\frac{4}{5}\)
\(-\frac{4}{5}< \frac{35}{-44}\)
\(\Rightarrow-\frac{92}{111}< \frac{35}{-44}\)
_HT_
\(\frac{-92}{111}\)\(=\frac{-4}{5}\)
\(\frac{-4}{5}\)\(< \frac{35}{-44}\)
\(\Rightarrow< \)
5332= (52)166 =25166 < 27166 = (33)166 = 3498< 3501
=> 5332 < 3501
Vậy 5332 < 3501
\(\frac{72}{145}< \frac{72}{144}=\frac{1}{2}\)
\(\frac{250}{499}>\frac{250}{500}=\frac{1}{2}\)
\(\Rightarrow\frac{72}{145}< \frac{250}{499}\)
Ta có:\(\frac{111}{332}\)>\(\frac{111}{333}\)=\(\frac{1}{3}\)\(\Rightarrow\)\(\frac{111}{332}\)>\(\frac{1}{3}\)
\(\frac{166}{499}\)<\(\frac{166}{498}\)=\(\frac{1}{3}\)\(\Rightarrow\)\(\frac{166}{499}\)<\(\frac{1}{3}\)
\(\Rightarrow\)\(\frac{111}{332}\)>\(\frac{166}{499}\)
Vậy\(\frac{111}{332}\)>\(\frac{166}{499}\)