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Bài 1:
a) \(\dfrac{-5}{6}\ne\dfrac{10}{-14}\left(\dfrac{10}{-14}=-\dfrac{5}{7}\right).\)
b) \(\dfrac{-15}{-60}\ne\dfrac{-3}{12}\left(\dfrac{-15}{-60}=\dfrac{1}{4}\right).\)
Bài 2:
a) \(\dfrac{20}{-140}=-\dfrac{1}{7}.\)
b) \(\dfrac{4.18}{9.12}=\dfrac{72}{108}=\dfrac{2}{3}.\)
c) \(\dfrac{17.25-17.3}{2.\left(-15\right)}=\dfrac{17.\left(25-3\right)}{-30}=-\dfrac{17.22}{30}=\dfrac{374}{30}=\dfrac{187}{15}.\)
Bài 3:
a) \(\dfrac{-3}{5}< \dfrac{4}{-7}.\)
b) \(\dfrac{-4}{21}>\dfrac{-7}{35}.\)
c) \(\dfrac{-7}{24}>\dfrac{-2}{3}.\)
d) \(\dfrac{-52}{167}< \dfrac{-3}{-4}.\)
1)
\(A=\dfrac{5}{7}.\dfrac{-4}{13}+\dfrac{5}{7}.\dfrac{7}{13}-\dfrac{5}{13}.\dfrac{3}{7}\)
\(A=\dfrac{5}{7}.\dfrac{-4}{13}+\dfrac{5}{7}.\dfrac{7}{13}-\dfrac{5}{7}.\dfrac{3}{13}\)
\(A=\dfrac{5}{7}.\left(\dfrac{-4}{13}+\dfrac{7}{13}-\dfrac{3}{13}\right)\) (Tính chất phân phối của phép nhân đối với phép cộng)
\(A=\dfrac{5}{7}.0\) (Tính chất nhân với số 0)
\(A=0\)
2)
a) \(A=\dfrac{-6}{5}.\dfrac{1}{2}-\dfrac{-6}{5}.\dfrac{2}{3}+\dfrac{-6}{5}.\dfrac{3}{4}\)
\(A=\dfrac{-6}{5}.\left(\dfrac{1}{2}-\dfrac{2}{3}+\dfrac{3}{4}\right)\)
\(A=\dfrac{-6}{5}.\dfrac{7}{12}\)
\(A=\dfrac{-7}{10}\)
b) \(B=\dfrac{-1}{6}.\dfrac{-3}{7}+\dfrac{4}{3}.\dfrac{-3}{7}-\dfrac{1}{2}.\dfrac{-3}{7}\)
\(B=\dfrac{-3}{7}.\left(\dfrac{-1}{6}+\dfrac{4}{3}-\dfrac{1}{2}\right)\)
\(B=\dfrac{-3}{7}.\dfrac{2}{3}\)
\(B=\dfrac{-2}{7}\)
c) \(C=\dfrac{2013}{2014}.\dfrac{5}{4}+\dfrac{2013}{2014}.\dfrac{1}{6}-\dfrac{2013}{2014}.\dfrac{17}{12}\)
\(C=\dfrac{2013}{2014}.\left(\dfrac{5}{4}+\dfrac{1}{6}-\dfrac{17}{12}\right)\)
\(C=\dfrac{2013}{2014}.0\)
\(C=0\)
Bài 1:
a: -8/12<0<-3/-4
b: -56/24<0<7/3
c: 4/25<1<15/13
=>-4/25>-15/13
Bài 2:
a: =-60/45=-4/3
b: =4/15-3/2-8/5=8/30-45/30-48/30=-85/30=-17/6
Đáp án cần chọn là: D
A = 2 5 .7 + 2 5 2 5 .5 2 − 2 5 .3 = 2 5 . ( 7 + 1 ) 2 5 . ( 5 2 − 3 ) = 2 5 . ( 7 + 1 ) 2 5 . ( 25 − 3 ) = 2 5 .8 2 5 .22 = 8 22 = 4 11 B = 3 4 .5 − 3 6 3 4 .13 + 3 4 = 3 4 . ( 5 − 3 2 ) 3 4 . ( 13 + 1 ) = 3 4 . ( 5 − 9 ) 3 4 .14 = 3 4 . ( − 4 ) 3 4 .14 = − 4 14 = − 2 7
MSC = 77
4 11 = 4.7 11.7 = 28 77 ; − 2 7 = − 2.11 7.11 = − 22 77
Do đó − 22 77 < 28 77 < 1 hay B < A < 1