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23-23.5 phần 4-27=23.(1-5)phần -23=23.-4 phần -23=-23.4 phần -23=4
Đáp số 4
a,\(4+6+8+...+40=\frac{\left(40+4\right).[\left(40-4\right):2+1]}{2}=\frac{44.19}{2}=418\)
b,\(3+7+11+...+31=\frac{\left(31+3\right).8}{2}=\frac{34.8}{2}=136\)
c,\(5+10+15+...+105=\frac{\left(105+5\right).[\left(105-5\right):5+1]}{2}=\frac{110.21}{2}=1155\)
rút gọn
a, 4+6+8+...+40
\(=\frac{\left[\left(40-4\right):2\right].\left(40+2\right)}{2}=\frac{756}{2}=378\)
b, 3 + 7 + 11 + 15 + 19 + 23 + 27 + 31
\(=\frac{\left[\left(31-3\right):4\right].\left(31+3\right)}{2}=\frac{238}{2}=119\)
c, 5 + 10 + 15 +...+105
\(=\frac{\left[\left(105-5\right):5\right].\left(105+5\right)}{2}=\frac{2200}{2}=1100\)
Study well
Câu 3:
a) \(\dfrac{12}{36}=\dfrac{12:12}{36:12}=\dfrac{1}{3}\)
\(\dfrac{-16}{20}=\dfrac{-16:4}{20:4}=\dfrac{-4}{5}\)
b) \(\dfrac{21}{105}=\dfrac{21:21}{105:21}=\dfrac{1}{5}\)
\(\dfrac{35}{150}=\dfrac{35:5}{150:5}=\dfrac{7}{30}\)
Câu 4:
a) \(\dfrac{3}{10}+\dfrac{5}{10}=\dfrac{3+5}{10}=\dfrac{8}{10}=\dfrac{4}{5}\)
b) Ta có: \(\left(-27\right)\cdot36+64\cdot\left(-27\right)+23\cdot\left(-100\right)\)
\(=\left(-27\right)\cdot\left(64+36\right)+23\cdot\left(-100\right)\)
\(=-27\cdot100-23\cdot100\)
\(=100\left(-27-23\right)\)
\(=-50\cdot100=-5000\)
c) \(\dfrac{5}{8}+\dfrac{3}{12}=\dfrac{15}{24}+\dfrac{6}{24}=\dfrac{21}{24}=\dfrac{7}{8}\)
d) Ta có: \(\dfrac{-2}{17}+\dfrac{3}{19}+\dfrac{-15}{17}+\dfrac{16}{19}+\dfrac{5}{6}\)
\(=\left(-\dfrac{2}{17}+\dfrac{-15}{17}\right)+\left(\dfrac{3}{19}+\dfrac{16}{19}\right)+\dfrac{5}{6}\)
\(=-1+1+\dfrac{5}{6}\)
\(=\dfrac{5}{6}\)
Theo đề, ta có: \(\dfrac{23-b}{27-b}=\dfrac{5}{6}\)
\(\Leftrightarrow138-6b=135-5b\)
\(\Leftrightarrow-6b+5b=135-138=-3\)
hay b=3
bn ơi / đây là chia hay phần??
Nếu đề là \(\frac{23.5-23}{4-27}\) thì ok :v
\(\frac{23.5-23}{4-27}=\frac{23.5-23}{-23}=\frac{23.\left(5-1\right)}{-23}=\frac{23.4}{-23}=\frac{92}{-23}\)