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\(a,\frac{121.75.130.169}{39.60.11.198}=\frac{11^2.5^2.3.13.2.5.13^2}{13.3.5.2^2.3.11.3^2.2.11}\)\(=\frac{11^2.5^3.3.13^3.2}{13.3^4.5.2^3.11^2}=\frac{5^2.13^2}{3^3.2^2}=\frac{4425}{108}\)
\(b,\frac{1989.1990+3978}{1992.1991-3984}=\frac{1989.1990+1989.2}{1992.1991-1992.2}\)\(=\frac{1989\left(1990+2\right)}{1992\left(1991-2\right)}=\frac{1989.1992}{1992.1989}=\frac{1}{1}=1\)
\(c.\frac{135.350+135.550}{900.100+35.900}=\frac{135\left(350+550\right)}{900\left(100+35\right)}=\)\(\frac{135.900}{900.135}=\frac{1}{1}=1\)
\(d.\frac{243.650-243.350}{600.200+600.43}=\frac{243\left(650-350\right)}{600\left(200+43\right)}\)\(=\frac{243.300}{600.243}=\frac{300}{600}=\frac{1}{2}\)
135.350 + 135.550/900.100 + 35.900=
135. (350+550) / 900. (100+35)=
135. 900 / 900. 135=
135. (900+900) =
135. 1800 = 243 000
\(\frac{121\cdot75\cdot130\cdot169}{39\cdot60\cdot11\cdot198}=\frac{11^2\cdot3\cdot5^2\cdot13\cdot2\cdot5\cdot13^2}{13\cdot3\cdot2^2\cdot3\cdot5\cdot11\cdot2\cdot11\cdot3^2}\)
\(=\frac{11^2\cdot3\cdot5^3\cdot13^3\cdot2}{13\cdot3^4\cdot2^3\cdot5\cdot11^2}=\frac{13\cdot5^2}{3^3\cdot2^2}=\frac{325}{36}\)
P/S:Không bt có đúng ko nx nhưng hướng làm là như vậy
\(\dfrac{121.75.130.169}{39.60.11.198}=\dfrac{11^2.3.5^2.2.5.13.13^2}{3.13.2^2.3.5.11.2.3^2.11}=\dfrac{2.3.5^3.11^2.13^3}{2^3.3^4.5.11^2.13}=\dfrac{5^2.13^2}{2^2.3^3}=\dfrac{4225}{108}\)
=\(\dfrac{121.75.130.169}{39.60.11.198}\)
=\(\dfrac{25.65.13.13}{13.30.18}\)
=\(\dfrac{5.5.65.13.13}{13.6.5.18}\)
=\(\dfrac{5.65.13}{6.18}\)
=\(\dfrac{65.65}{108}\)
=\(\dfrac{4225}{108}\)
Chúc bạn học tốt !
\(\left(1\right)\frac{121.75.130.169}{39.60.11.198}\)
\(=\frac{121.15.5.13.10.13.13}{13.3.15.4.11.18.11}\)
\(=\frac{121.5.13^2.10}{3.4.18.121}\)
\(=\frac{50.196}{12.18}\)
\(=\frac{9800}{216}=\frac{1225}{27}\)
\(\left(2\right)\frac{135.350+135.550}{900.100+35.900}\)
\(=\frac{135.\left(350+550\right)}{900.\left(100+35\right)}\)
\(=\frac{135.900}{900.135}=1\)
HOK TOT
1)=11^2.15.5.13.10.169/13.3.15.4.11.198
=5.10.169/3.4.18
=8450/216=4225/108
2)=135.(350+550)/900.(100+35)
=135.900/900.135=1