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CB
3
15 tháng 6 2016
2p=24(5^2+1)(5^4+1)(5^8+1)(5^16+1)
=(5^2-1)(5^2+1)(5^4+1)(5^8+1)(5^16+1)
=(5^4-1)(5^4+1)(5^8+1)(5^16+1)
=(5^8-1)(5^8+1)(5^16+1)
=(5^16-1)(5^16+1)
=5^32-1
~> p=5^32-1/2
15 tháng 6 2016
\(2P=24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)
\(2P=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)
\(2P=\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)
\(2P=\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)
\(2P=\left(5^{16}-1\right)\left(5^{16}+1\right)\)
\(2P=5^{32}-1\)
\(p=\frac{5^{32}-1}{2}\)
TV
1
9 tháng 12 2016
2p=24(52+1)(54+1)(58+1)(516+1)2p=24(52+1)(54+1)(58+1)(516+1)
=(52−1)(52+1)(54+1)(58+1)(516+1)=(52−1)(52+1)(54+1)(58+1)(516+1)
=(54−1)(54+1)(58+1)(516+1)=(54−1)(54+1)(58+1)(516+1)
=(58−1)(58+1)(516+1)=(58−1)(58+1)(516+1)
=(516−1)(516+1)=(516−1)(516+1)
=532−1 >p=5322
TP
1
VM
19 tháng 8 2020
Đặt 
\(A=12.\left(5^2+1\right).\left(5^4+1\right).\left(5^8+1\right).\left(5^{16}+1\right)\)
\(\Rightarrow2A=24.\left(5^2+1\right).\left(5^4+1\right).\left(5^8+1\right).\left(5^{16}+1\right)\)
\(2A=\left(5^2-1\right).\left(5^2+1\right).\left(5^4+1\right).\left(5^8+1\right).\left(5^{16}+1\right)\)
\(2A=\left(5^4-1\right).\left(5^4+1\right).\left(5^8+1\right).\left(5^{16}+1\right)\)
\(2A=\left(5^8-1\right).\left(5^8+1\right).\left(5^{16}+1\right)\)
\(2A=\left(5^{16}-1\right).\left(5^{16}+1\right)\)
\(2A=\left(5^{16}\right)^2-1^2\)
\(2A=5^{32}-1\)
\(\Rightarrow A=\frac{5^{32}-1}{2}.\)
HT
0
MA
0
SX
1
27 tháng 9 2015
2P = 24.(5^2 + 1 )( 5^4 + 1 ) (5^8 + 1 )(5^16 + 1 )
2P = ( 5^2 - 1 )((5^2 + 1 )( 5^4 + 1 ) (5^ 8 + 1 )( 5^ 16 + 1)
2P = ( 5 ^ 4 - 1 )( 5 ^ 4 + 1 ) (5^8 + 1 )(5^16 + 1 )
2P = ( 5 ^8 - 1 )( 5^8 + 1 )( 5^16 + 1)
2P = ( 5 ^16 - 1 )( 5^16 + 1 )
2P = 5^32 - 1
=> P = \(\frac{5^{32}-1}{2}\)
TM
1
DK
13 tháng 9 2017
Nhân cả 2 vế với 2 ta có:
2P=24(52+1)(54+1)(58+1)(516+1)
2P=(52_1)(52+1)(54+1)(58+1)(516+1)
2P=(54_1)(54+1)(58+1)(516+1)
2P=(58_1)(58+1)(516+1)
2P=(516_1)(516+1)
2P=532_1
P=\(\frac{5^{32}-1}{2}\)
\(P=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)
\(=\dfrac{\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)
\(=\dfrac{\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)
\(=\dfrac{\left(5^{16}-1\right)\left(5^{16}+1\right)}{2}\)
\(=\dfrac{5^{32}-1}{2}\)
\(P=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)
\(2P=\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{32}+1\right)\)
\(2P\)\(=\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)
\(2P=\)\(\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)
\(2P=\left(5^{16}-1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\)
\(2P=5^{32}-1\)
\(P=\dfrac{5^{32}-1}{2}\)