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a) \(27x^3+27x^2+9x+1=\left(3x+1\right)^3\)
b) \(-x^3-3x^2-3x-1=-\left(x^3+3x^2+3x+1\right)=-\left(x+1\right)^3\)
c) \(-8+12x-6x^2+x^3=\left(x-2\right)^3\)
a) \(x^3+9x^2+27x+27=\left(x+3\right)^3\)
b) \(3\sqrt{3x^3}+18x^2+12\sqrt{3x}+8=\left(\sqrt{3x}+2\right)^3\)
c) \(\dfrac{1}{4}-x^2=\left(\dfrac{1}{2}-x\right)\left(\dfrac{1}{2}+x\right)\)
=X4-3X3 +6X3-18X2+11X2-33X+6X-18
=(X-3)(X3+6X2+11X+6)
=(X-3)(X+3)(X+1)(X+2)
\(x^4+3x^3-7x^2-27x-18.\)
\(=\left(x^4-9x^2\right)+\left(3x^3-27x\right)+\left(2x^2-18\right)\)
\(=x^2\left(x-3\right)\left(x+3\right)+3x\left(x-3\right)\left(x+3\right)+2\left(x-3\right)\left(x+3\right).\)
\(=\left(x-3\right)\left(x+3\right)\left(x^2+3x+2\right)\)
\(=\left(x-3\right)\left(x+3\right)\left(x^2+x+2x+2\right)\)
\(=\left(x-3\right)\left(x+3\right)\left(x+1\right)\left(x+2\right).\)
\(x^3+3x^2+3x+1-27x^3=-26x^3+3x^2+3x+1\)
\(=-26x^3+13x^2-10x^2+5x-2x+1\)
\(=\left(2x-1\right).\left(-13x^2-5x-1\right)\)