Question

[Nguyễn Thị Phương Thảo]

NHan cac don thuc sau va tim bac va he so cua don thuc nhan duoc:

(\(\dfrac{1}{3}\)x\(^3\)y).(-xy)\(^2\)

Answer 1

[Gia Hân Ngô]

\(\left(\dfrac{1}{3}x^3y\right)\left(-xy\right)^2=\left(\dfrac{1}{3}x^3y\right).x^2y^2=\dfrac{1}{3}x^5y^3\)

Bậc: 5

Hệ số: \(\dfrac{1}{3}\)