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\(\dfrac{7y+1}{y-5}+\dfrac{2}{y-5}=\dfrac{7y+3}{y-5}\)
sory doan cuoi minh lam sai minh lam lai nhe
pt<=>1/(y-1)(y-2) + 1/(y-2)(y-3) + 1/(y-3)(y-4) + 1(y-4)(y-5)=1/15
=>1/(y-1) -1/(y-2)+1/(y-2)-1/(y-3)+1/(y-3)-1/(y-4)+1/(y-4)-1/(y-5)=1/15
=>1/(y-1) - 1/(y-5)=1/15
=>4/(y-1)(y-5)=1/15
=> (y-1)(y-5)=60
=> y2-6y+5-60=0
=>y2-6y-55=0
=> (y-11)(y+5)=0
=>y=11 hoac y=-5
2)
a) \(\dfrac{1}{x}.\dfrac{6x}{y}\)
\(=\dfrac{6x}{xy}\)
\(=\dfrac{6}{y}\)
b) \(\dfrac{2x^2}{y}.3xy^2\)
\(=\dfrac{2x^2.3xy^2}{y}\)
\(=\dfrac{6x^3y^2}{y}\)
\(=6x^3y\)
c) \(\dfrac{15x}{7y^3}.\dfrac{2y^2}{x^2}\)
\(=\dfrac{15x.2y^2}{7y^3.x^2}\)
\(=\dfrac{30xy^2}{7x^2y^3}\)
\(=\dfrac{30}{7xy}\)
d) \(\dfrac{2x^2}{x-y}.\dfrac{y}{5x^3}\)
\(=\dfrac{2x^2.y}{\left(x-y\right).5x^3}\)
\(=\dfrac{2y}{5x\left(x-y\right)}\)