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\(a) C_6H_{12}O_6 \xrightarrow{t^o,xt} 2CO_2 + 2C_2H_5OH\\ C_2H_5OH + O_2 \xrightarrow{men\ giấm} CH_3COOH + H_2O\\ CH_3COOH + C_2H_5OH \to CH_3COOC_2H_5 + H_2O\\ b) C_{12}H_{22}O_{11} + H_2O \xrightarrow{H^+}C_6H_{12}O_6 + C_6H_{12}O_6\\ C_6H_{12}O_6 \xrightarrow{t^o,xt} 2CO_2 + 2C_2H_5OH\\C_2H_5OH + O_2 \xrightarrow{men\ giấm} CH_3COOH + H_2O\\ CH_3COOH + NaOH \to CH_3COONa + H_2O\\ c) CH_3COOC_2H_5 + NaOH \to CH_3COONa + C_2H_5OH\\ d) 2CH_3COOC_2H_5 + Ca(OH)_2 \to (CH_3COO)_2Ca + 2C_2H_5OH\)
\((CH_3COO)_2Ca + H_2SO_4 \to CaSO_4 + 2CH_3COOH\)
\(C_6H_{12}O_6\rightarrow^{men\text{r}ượu}_{t^0}2C_2H_5OH+2CO_2\)
\(C_2H_5OH+O_2\rightarrow^{men\text{gi}ấm}CH_3COOH+H_2O\)
\(CH_3COOH+C_2H_5OH\rightarrow^{H_2SO_4đặc}_{t^0}CH_3COOC_2H_5+H_2O\)
\(CH_3COOC_2H_5+H_2O\rightarrow^{H_2SO_4loãng}_{t^0}CH_3COOH+C_2H_5OH\)
\(2CH_3COOH+2Na\rightarrow2CH_3COONa+H_2\)
\(\left(-C_6H_{10}O_5-\right)_n+nH_2O\xrightarrow[t^o]{axit}nC_6H_{12}O_6\)
\(C_6H_{12}O_6\xrightarrow[]{men}2C_2H_5OH+2CO_2\)
\(C_2H_5OH+O_2\xrightarrow[]{men}CH_3COOH+H_2O\)
\(C_2H_5OH+CH_3COOH\xrightarrow[H_2SO_4\left(đ\right)]{t^o}CH_3COOC_2H_5+H_2O\)
\(CH_3COOC_2H_5+H_2O\xrightarrow[t^o]{xt}CH_3COOH+C_2H_5OH\)
\(\left(C_6H_{10}O_5\right)_n+nH_2O\underrightarrow{axit.loãng}nC_6H_{12}O_6\)
\(C_6H_{12}O_6\xrightarrow[30-35^oC]{enzim}2C_2H_5OH+2CO_2\)
\(C_2H_5OH+O_2\xrightarrow[25-30^oC]{men.giấm}CH_3COOH+H_2O\)
\(CH_3COOH+C_2H_5OH⇌\left(H_2SO_4đ,t^o\right)CH_3COOC_2H_5+H_2O\)
CaO + 3C => CaC2 + CO
CaC2 + 2H2O => Ca(OH)2 + C2H2 (axetilen)
3C2H2 => (cacbon hoạt tính, 600oC) C6H6
C6H6 + Br2 => HBr + C6H5Br (brom benzen)
C2H2 + H2 => (to,Pd) C2H4
C2H4 + H2O => (140oC, H2SO4đ) C2H5OH (rượu etylic)
C2H5OH + O2 => (men giấm) H2O + CH3COOH (axit axetic)
CH3COOH + C2H5OH => (to,H2SO4đ, pứ hai chiều) H2O + CH3COOC2H5 (etyl axetat)
n -(CH2-CH2)- => (to,xt,P) -(CH2-CH2)-n
Chị (anh) copy sai đề rồi ạ, mong chị (anh) xem lại đề và giải giúp em ạ.
(1) \(C_6H_{12}O_6\underrightarrow{t^o,xt}2C_2H_5OH+2CO_2\)
(2) \(C_2H_5OH+O_2\underrightarrow{^{mengiam}}CH_3COOH+H_2O\)
(3) \(CH_3COOH+NaOH\rightarrow CH_3COONa+H_2O\)
(4) \(CH_3COONa+NaOH\underrightarrow{^{CaO,t^o}}CH_4+Na_2CO_3\)
1/ 1/ (-C6H10O5-)n + nH2O => (H2SO4đ,to) nC6H12O6
C6H12O6 => (men rượu,to) 2CO2 + C2H5OH
C2H5OH + O2 => (men giấm) CH3COOH + H2O
CH3COOH + C2H5OH => (H2SO4đ,to) <pứ hai chiều> CH3COOC2H5 + H2O
2/ C2H4 + H2O => (140oC,H2SO4đ) C2H5OH
C2H5OH + O2 => (men giấm) CH3COOH + H2O
CH3COOH + C2H5OH => (H2SO4đ,t0) <pứ hai chiều> CH3COOC2H5 + H2O
CH3COOC2H5 + NaOH => (to) CH3COONa + C2H5OH
câu1
1/
(C6H10O5)n+ nH2O\(\xrightarrow[to]{axit}\) nC6H12O6
C6H12O6\(\xrightarrow[30-35\cdot C]{enzim}\) 2C2H5OH+ 2CO2\(\uparrow\)
C2H5OH+ O2\(\xrightarrow[giấm]{men}\) CH3COOH+ H2O
C2H5OH+ CH3COOH\(\xrightarrow[to]{H2SO4đặc}\) CH3COOC2H5+ H2O
2/
C2H4+ H2O\(\xrightarrow[]{axit}\) C2H5OH
C2H5OH+ O2\(\xrightarrow[giấm]{men}\) CH3COOH+ H2O
C2H5OH+ CH3COOH\(\xrightarrow[to]{H2SO4đặc}\) CH3COOC2H5+ H2O
CH3COOC2H5+ H2O\(\xrightarrow[]{axit}\) C2H5OH+ CH3COOH
câu 2
a/
có: Vrượu= \(\frac{500.60}{100}\)= 300( ml)
b/
có: mrượu= V. D= 300. 0,8= 240( g)
1. C6H12O6-->C2H5OH-->CH3COOH--->CH3COOC2H5
C6H12O6->2C2H5OH + 2CO2 (1)
C2H5OH + O2 -> CH3COOH + H2O (2)
CH3COOH + C2H5OH->CH3COOC2H5 + H2O (3)
2.,CaC2 + H2O -> C2H2 + Ca(OH)2 (1)
C2H2 + H2 -> C2H4 (2)
n(C2H4)-> (C2H4)n ( trùng hợp )