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Ta suy ra:
x+3/y+5 = x+5/y+7 = (x+3-x-5)/(y+5-y-7) = -2/-2 =1
x+3 /y+5 =1 => x+3 =y+5
=> x-y = 5-3 =2
Vay x-y =2
Ap dung tinh chat day ti so bang nhau :
x+3/y+5=x+5/y+7=(x+5)-(x+3)/(y+7)-(y+5)=x+5-x-3/y+7-y-5=2/2=1
Suy ra : x+3/y+5=1=>x+3=y/5
=>x-y=5-3=2
Vay x-y=2
**** nhe
\(\frac{x+3}{y+5}=\frac{x+5}{y+7}=\frac{x+5-x-3}{y+7-y-5}=\frac{2}{2}=1\)
x+3 =y+5 => x -y = 5 -3 = 2
Vậy x -y =2
\(\frac{x+3}{y+5}=\frac{x+5}{y+7}=\frac{x+5-x-3}{y+7-y-5}=\frac{2}{2}=1\)
\(x+3=y+5\Leftrightarrow x-y=5-3=2\)
Ap dung tinh chat day ti so bang nhau :
\(\frac{x+3}{y+5}=\frac{x+5}{y+7}\Rightarrow\left(x+3\right)\left(y+7\right)=\left(y+5\right)\left(x+5\right)\)
\(\Rightarrow xy+7x+3y+21=xy+5x+5y+25\)
\(\Rightarrow7x+3y=5x+5y+25-21\)
\(7x-5x=5y-3y+4\)
\(2x=2y+4\Rightarrow2x-2y=4\)
\(2\left(x-y\right)=4\Rightarrow x-y=4:2=2\)
Vay :x-y=2
**** nhe
- Tu (x+3)/(y+5)=(x+5)/(y+7) suy ra xy+3y+7x+21=xy+5y+5x+25 \(\Rightarrow\)3y+7x=5y+5x+4\(\Rightarrow\)2x=2y+4=2(y+2)\(\Rightarrow\)x=y+2\(\Rightarrow\)x-y=2.
- \(\left(2x\right)^3=y^3\Rightarrow2x=y\Rightarrow\frac{x}{y}=\frac{x}{2x}=\frac{1}{2}\)
Áp dụng tính chất dãy tỉ số bằng nhau, ta có:
\(\frac{x+3}{y+5}=\frac{x+5}{y+7}=\frac{\left(x+3\right)-\left(x+5\right)}{\left(y-5\right)-\left(y+7\right)}=\frac{x+3-x+5}{y+5-y+7}=\frac{3-5}{5-7}=\frac{-2}{-2}=1\)
\(\Rightarrow\frac{x+3}{y+5}=\frac{x+5}{y+7}=1\)
\(\Rightarrow\left(x+3\right).1=\left(y+5\right).1\)
\(\Rightarrow x+3=y+5\)
\(\Rightarrow x-y=5-3\)
\(\Rightarrow x-y=2\)
Vậy x - y = 2.