Question

[Nguyễn thanh]

Giúp mk đề bài ở bình luận Mk cần gấp nha

Answer 1

[nguyen thi vang]

\(A^3_n+5A^2_n=2\left(n+15\right)\)

ĐK: n ≥ 3 (n∈N)

<=> \(\dfrac{n!}{\left(n-3\right)!}+\dfrac{5.n!}{\left(n-2\right)!}=2\left(n+15\right)\)

<=> \(\dfrac{n\left(n-1\right)\left(n-2\right)\left(n-3\right)!}{\left(n-3\right)!}+\dfrac{5n\left(n-1\right)\left(n-2\right)!}{\left(n-2\right)!}=2\left(n+15\right)\)

<=> \(n\left(n-1\right)\left(n-2\right)+5\left(n-1\right)n-2n-30=0\)

<=> \(n^3+2n^2-5n-30=0\) <=> n=3

Answer 2

[Nguyễn thanh]