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a) | x - 1,5 | = 2
=>x - 1,5 =2 hoặc x - 1,5 = -2
Th1:
x - 1,5 =2
x=2+1,5
x=3,5
Th2:
x - 1,5 = -2
x=-2+1,5
x=-0,5
Vậy x\(\in\){3,5:-0,5}
a)
| x - 1,5 | = 2
+) x - 1,5 = 2
=> x = 3,5
+) x - 1,5 = -2
=> x = -0,5
b) c) tường tự
haiz
b) | x + 3/4 | - 1/2 = 0
| x + 3/4 | = 1/2
+) x + 3/4 = 1/2
=> x = -1/4
+) x + 3/4 = -1/2
=> x = -5/4
Vậy,.......
| x + 4/15 | - | - 3,75 | = - | - 2,15 |
| x + 4/15 | - 3,75 = - 2,15
| x + 4/15 | = - 2,15 + 3,75
| x + 4/15 | = 1,6
Trường hợp 1 : x + 4/15 = 1,6 suy ra x = 4/3
Trương hợp 2: x + 4/15 = - 1,6 suy ra x = -28/15
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\Rightarrow\left|x+\frac{4}{15}\right|-3,75=-2,15\)
\(\Rightarrow\left|x+\frac{4}{15}\right|=-2,15+3,75\)
\(\Rightarrow\left|x+\frac{4}{15}\right|=1,6\)
\(\Rightarrow\left|x+\frac{4}{15}\right|=\frac{8}{5}\)
\(\Rightarrow\left[\begin{array}{nghiempt}x+\frac{4}{15}=\frac{8}{5}\\x+\frac{4}{15}=-\frac{8}{5}\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{4}{3}\\x=-\frac{28}{15}\end{array}\right.\)
Ta có : \(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\Leftrightarrow\left|x+\frac{4}{15}\right|=3,75-2,15=\frac{8}{5}\)
\(\Rightarrow\left[\begin{array}{nghiempt}x+\frac{4}{15}=\frac{8}{5}\\-x-\frac{4}{15}=\frac{8}{5}\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=\frac{4}{3}\\x=-\frac{28}{15}\end{array}\right.\)
|x+4/15|-|-375|=-|-2,15|
|x+4/15|-375=-2,15
|x+4/15|=(-2,15)+375
|x+4/15|=372,85
<=> x+4/15=372,85 hoặc x+4/15=-372,85
<=>x=4471/12 hoặc x=-22387/60
Vậy x € { 4471/12 ; -22387/60 }
\(\left|x+\frac{4}{15}\right|-375=\) \(-2,15\)
<=>\(\left|x+\frac{4}{15}\right|=372,85\)
<=> \(\hept{\begin{cases}x+\frac{4}{15}=372,85\\x+\frac{4}{15}=-372,85\end{cases}}\)
<=> \(\hept{\begin{cases}x=\frac{4471}{12}\\x=\frac{-22387}{60}\end{cases}}\)
/x+4/15/-/-3,75/=-/-2,15/
/x+4/15/-15/4=-\(\frac{43}{20}\)
x+4/15=\(\frac{43}{20}+\frac{15}{4}\)
x+4/15=59/10
x=59/10-4/15
x=\(5\frac{19}{30}\)
/x + \(\frac{4}{15}\)/ - 3,75 = -2,15
=> /x + \(\frac{4}{15}\)/ = 1,6
=> \(x+\frac{4}{5}=1,6\) hoặc \(x+\frac{4}{5}=-1,6\)
=> \(x=0,8\)hoặc \(x=-2,4\)
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\left|x+\frac{4}{15}\right|-3,75=-2,15\)
\(\left|x+\frac{4}{15}\right|=-2,15+3,75\)
\(\left|x+\frac{4}{15}\right|=1,6\)
Ta có 2 trường hợp
trường hợp 1
\(x+\frac{4}{15}=1,6\)
\(x=1,6-\frac{4}{15}\)
\(x=\frac{4}{3}\)
Trường hợp 2
\(x+\frac{4}{15}=-1,6\)
\(x=-1,6-\frac{4}{15}\)
\(x=\frac{-28}{15}\)
Vậy \(x=\left\{-\frac{28}{15};\frac{4}{3}\right\}\)
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
=> \(\left|x+\frac{4}{15}\right|-3,75=-2,15\)
=> \(\left|x+\frac{4}{15}\right|=-2,15+3,75\)
=> \(\left|x+\frac{4}{15}\right|=1,6=\frac{8}{5}\)
=> \(\orbr{\begin{cases}x+\frac{4}{15}=\frac{8}{5}\\x+\frac{4}{15}=\frac{-8}{5}\end{cases}}\)=> \(\orbr{\begin{cases}x=\frac{4}{3}\\x=\frac{-28}{15}\end{cases}}\)
| x+ 4/15| - |-3,75| = - |- 2,15|
|x + 4/15| - 3,75 = - 2,15
|x + 4/15| = 8/5
Th1: x+4/15 = -8/5
x= -8/5 - 4/15
x= -28/15
Th2: x + 4/15 = 8/5
x= 8/5 - 4/15
x= 4/3
Vậy x= -28/15 ; 4/3