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a: \(\dfrac{x}{-3}=\dfrac{-5}{15}\)
nên x=1
b: \(\dfrac{1173}{x}=\dfrac{3}{5}\)
nên \(x=\dfrac{1173}{3}\cdot5=1955\)
a) (17.x - 25 ) : 8 = 92 : 65= 92/65
17x - 25 = 92/65.8
17x = 2361/65
x= 2361/65 : 17=2361/1105
b) x- 60 = 2017101 - 2017100
x-60 = 2017
x = 2017 + 60
x = 2077
c) 5x . 30-3x.x = 45
5x.3x.x = 45 + 30 = 75
15x.x = 75
a)
\(5x+60=120\)
\(\Rightarrow5x=120-60\)
\(\Rightarrow5x=60\)
\(\Rightarrow x=60\div5\)
\(\Rightarrow x=12\)
Vậy \(x=12\)
b)
\(213-\left(x+25\right)=112\)
\(\Rightarrow x+25=213-112\)
\(\Rightarrow x+25=101\)
\(\Rightarrow x=101-25\)
\(\Rightarrow x=76\)
Vậy \(x=76\)
c)
\(5^x-25=100\)
\(\Rightarrow5^x=100+25\)
\(\Rightarrow5^x=125\)
\(\Rightarrow5^x=5^3\)
\(\Rightarrow x=3\)
Vậy \(x=3\)
\(6\cdot x-5=613\)
\(6\cdot x=613+5\)
\(6\cdot x=618\)
\(x=618\div6\)
\(x=103\)
Vậy \(x=103\)
\(12\cdot x+3\cdot x=30\)
\(x\cdot\left(12+3\right)=30\)
\(x\cdot15=30\)
\(x=30\div15\)
\(x=2\)
Vậy \(x=2\)
\(125-25\cdot\left(x-1\right)=100\)
\(25\cdot\left(x-1\right)=125-100\)
\(25\cdot\left(x-1\right)=25\)
\(x-1=25\div25\)
\(x-1=1\)
\(x=1+1\)
\(x=2\)
Vậy \(x=2\)
\(\left(x-2\right)\cdot\left(x-14\right)=0\)
\(\Rightarrow\) \(x-2=0\) hoặc \(x-14=0\)
TH1: \(x-2=0\) TH2: \(x-14=0\)
\(x=0+2\) \(x=0+14\)
\(x=2\) \(x=14\)
Vậy \(x=2\) hoặc \(x=14\)
\(128-3\cdot\left(x+4\right)=23\)
\(3\cdot\left(x+4\right)=128-23\)
\(3\cdot\left(x+4\right)=105\)
\(x+4=105\div3\)
\(x+4=35\)
\(x=35-4\)
\(x=31\)
Vậy \(x=31\)
12.x+3.x=30
x.(12+3)=30
x.15=30
x =30:15
x =2
125-25.(x-1)=100
25.(x-1)=125-100
25.(x-1)=25
x-1=25:25
x-1=1
x =1+1
x=2
(x-2).(x-14)=0
x=14
128-3.(x+4)=23
3.(x+4)=128-23
3.(x+4)=105
x+4=105:3
x+4=35
x = 35+4
x =39