Question

[Vũ Thu Hiền]

Giải giúp mình câu 2,6,7,8,9,10

Bài ở dưới cmt

Answer 1

[Nguyễn Lê Phước Thịnh]

2: Ta có: \(\sqrt{14-8\sqrt{3}}\)

\(=\sqrt{8-2\cdot\sqrt{8}\cdot\sqrt{6}+6}\)

\(=\sqrt{\left(2\sqrt{3}-\sqrt{6}\right)^2}\)

\(=\left|2\sqrt{3}-\sqrt{6}\right|\)

\(=2\sqrt{3}-\sqrt{6}\)

6: Ta có: \(\sqrt{13+4\sqrt{10}}\)

\(=\sqrt{8+2\cdot\sqrt{8}\cdot\sqrt{5}+5}\)

\(=\sqrt{\left(2\sqrt{2}+\sqrt{5}\right)^2}\)

\(=\left|2\sqrt{2}+\sqrt{5}\right|\)

\(=2\sqrt{2}+\sqrt{5}\)

7: Ta có: \(\sqrt{35-12\sqrt{6}}\)

\(=\sqrt{27-2\cdot\sqrt{27}\cdot\sqrt{8}+8}\)

\(=\sqrt{\left(3\sqrt{3}-2\sqrt{2}\right)^2}\)

\(=\left|3\sqrt{3}-2\sqrt{2}\right|\)

\(=3\sqrt{3}-2\sqrt{2}\)

Answer 2

[Vũ Thu Hiền]

https://i.imgur.com/Unvysau.jpg