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Ta có:\(\frac{2x+2}{3x-6}=\frac{2x-6}{3x-15}\)
\(\Rightarrow\frac{2\left(x+1\right)}{3\left(x-2\right)}=\frac{2\left(x-3\right)}{3\left(x-5\right)}\)
\(\Rightarrow\frac{2}{3}\cdot\frac{x+1}{x-2}=\frac{2}{3}\cdot\frac{x-3}{x-5}\)
\(\Rightarrow\frac{x+1}{x-2}=\frac{x-3}{x-5}\)
\(\Rightarrow\frac{x+1}{x-2}-1=\frac{x-3}{x-5}-1\)
\(\Rightarrow\frac{x+1-x+2}{x-2}=\frac{x-3-x+5}{x-5}\)
\(\Rightarrow\frac{3}{x-2}=\frac{2}{x-5}\)
\(\Rightarrow3\left(x-5\right)=2\left(x-2\right)\)
\(\Rightarrow3x-15=2x-4\)
\(\Rightarrow3x-2x=-4+15\)
\(\Rightarrow x=11\)
Ta có: \(\frac{3x}{4}\)= \(\frac{y}{2}\)= \(\frac{3z}{5}\)
=> \(\frac{1}{3}.\frac{3x}{4}=\frac{1}{3}.\frac{y}{2}=\frac{1}{3}.\frac{3z}{5}\)
\(\Rightarrow\frac{3x}{12}=\frac{y}{6}=\frac{3z}{15}\)
\(\Rightarrow\frac{x}{4}=\frac{y}{6}=\frac{z}{5}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\frac{x}{4}=\frac{y}{6}=\frac{z}{5}=\frac{y-z}{6-5}=15\)
Suy ra:
- x = 15.4=60
- y=15.6=90
- z=15.5=75
\(\Rightarrow\)x + y + z = 225
=> (2x+2)(3x-15) = (3x-6)(2x-6)
=> 6x2-30x+6x-30 = 6x2-18x-12x+36
=> 6x2-30x+6x-30-6x2+18x+12x-36 = 0
=> 6x - 96 = 0
=> 6x = 96
=> x = 96/6
=> x = 16
Vậy x = 16
\(A=\frac{x^2-10x+36}{x-5}=\frac{x^2-10x+25+9}{x-5}\) \(=\frac{\left(x-5\right)^2+9}{x-5}=x-5+\frac{9}{x-5}\)
để \(A\in Z\)
<=> \(\frac{9}{x-5}\in Z\)mà \(x\in Z\)
=> \(x-5\inƯ\left(9\right)\)
=> \(x-5\in\left(1;-1;3;-3;9;-9\right)\)
=> \(x\in\left(6;4;8;2;14;-4\right)\)
học tốt
Từ giả thiết suy ra 2x.3x=42.28
=> 6x2 =1176
=> x2 = 196
=> x= 14 hoặc x=-14
\(\frac{2x+2}{3x-6}=\frac{2x-6}{3x-15}\)
\(\Rightarrow\left(2x+2\right)\left(3x-15\right)=\left(2x-6\right)\left(3x-6\right)\)
\(\Rightarrow6x^2-30x+6x-30=6x^2-12x-18x+36\)
\(\Rightarrow6x^2-30x+6x-6x^2+12x+18x=36+30\)
\(\Rightarrow6x=66\)
\(\Rightarrow x=11\)
k mk nha