Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\frac{3}{8}+\frac{4}{5}=\frac{15}{40}+\frac{32}{40}=\frac{47}{40}\)
a) \(\left(x+\frac{7}{4}\right)\times\frac{3}{2}=6\)
\(\Leftrightarrow\left(x+\frac{7}{4}\right)=6\div\frac{3}{2}\)
\(\Leftrightarrow x+\frac{7}{4}=4\)
\(\Leftrightarrow x=4-\frac{7}{4}\)
\(\Leftrightarrow x=\frac{9}{4}\)
b) \(x\div\frac{3}{5}+\frac{2}{5}=\frac{9}{5}\)
\(\Leftrightarrow x\div\frac{3}{5}=\frac{9}{5}-\frac{2}{5}\)
\(\Leftrightarrow x\div\frac{3}{5}=\frac{7}{5}\)
\(\Leftrightarrow x=\frac{7}{5}\times\frac{3}{5}\)
\(\Leftrightarrow x=\frac{21}{25}\)
c) \(\frac{1}{2}\div3+x=\frac{5}{3}\)
\(\Leftrightarrow\frac{1}{6}+x=\frac{5}{3}\)
\(\Leftrightarrow x=\frac{5}{3}-\frac{1}{6}\)
\(\Leftrightarrow x=\frac{3}{2}\)
\(\frac{8}{11}+\frac{8}{33}\times\frac{3}{4}\)
\(=\frac{8}{11}+\frac{2}{11}\)
\(=\frac{8+2}{11}\)
\(=\frac{10}{11}\)
\(\frac{8}{11}+\frac{8}{33}\cdot\frac{3}{4}=\frac{8}{11}+\frac{8\cdot3}{33\cdot4}=\frac{8}{11}+\frac{2}{11}=\frac{10}{11}\)
\(x=\frac{1}{2}+\frac{3}{4}=\frac{2}{4}+\frac{3}{4}=\frac{5}{4}\)
\(x-\frac{3}{4}=\frac{1}{2}\)
\(x=\frac{1}{2}+\frac{3}{4}\)
\(x=\frac{2}{4}+\frac{3}{4}\)
\(x=\frac{5}{4}\)
\(\frac{2}{3}\) + \(\frac{3}{4}\) = \(\frac{8}{12}\) + \(\frac{9}{12}\) = \(\frac{17}{12}\)
\(\frac{5}{6}\) x \(\frac{4}{15}\) = \(\frac{2}{9}\)
\(\frac{4}{5}\) - \(\frac{2}{7}\) = \(\frac{28}{35}\) - \(\frac{10}{35}\) = \(\frac{18}{35}\)
\(\frac{13}{9}\) : \(\frac{5}{6}\) = \(\frac{13}{9}\) x \(\frac{6}{5}\) = \(\frac{26}{15}\)
chúc bạn hok tốt !
\(\frac{2}{3}+\frac{3}{4}=\frac{8}{12}+\frac{9}{12}=\frac{17}{12}\)
\(\frac{5}{6}\) x \(\frac{4}{15}\) \(=\frac{5x6}{6x15}=\frac{1}{3}\)
\(\frac{4}{5}-\frac{2}{7}=\frac{28}{35}-\frac{10}{35}=\frac{18}{35}\)
\(\frac{13}{9}:\frac{5}{6}=\frac{13}{9}x\frac{6}{5}=\frac{13x6}{9x5}=\frac{26}{15}\)
Chúc bạn học tốt !
\(\text{số cần tìm là }:\)
\(\frac{20}{9}-\frac{15}{8}=\frac{25}{72}\)
\(\text{ Đáp số :..........}\)
\(\frac{20}{9}-\frac{15}{8}=\frac{160}{72}-\frac{135}{72}=\frac{25}{72}\)
\(\frac{3}{2}+\frac{3}{8}+\frac{3}{32}+\frac{3}{128}+\frac{3}{512}\)
\(=3.\left(\frac{1}{2}+\frac{1}{2^3}+\frac{1}{2^5}+\frac{1}{2^7}+\frac{1}{2^9}\right)\)
\(=3.A\)với \(A=\frac{1}{2}+\frac{1}{2^3}+\frac{1}{2^5}+\frac{1}{2^7}+\frac{1}{2^9}\)
\(\Rightarrow2^2A=\left(2+\frac{1}{2}+\frac{1}{2^3}+\frac{1}{2^5}+\frac{1}{2^7}\right)\)
\(\Rightarrow2^2A-A=\left(2+\frac{1}{2}+\frac{1}{2^3}+\frac{1}{2^5}+\frac{1}{2^7}\right)-\left(\frac{1}{2}+\frac{1}{2^3}+\frac{1}{2^5}+\frac{1}{2^7}+\frac{1}{2^9}\right)\)
\(\Rightarrow4A-A=2-\frac{1}{2^9}\)
\(\Rightarrow3A=2-\frac{1}{512}=\frac{1023}{512}\Rightarrow A=\frac{1023}{512}:3\)
\(\Rightarrow\frac{3}{2}+\frac{3}{8}+\frac{3}{32}+\frac{3}{128}+\frac{3}{512}=3.\left(\frac{1023}{512}:3\right)=\frac{1023}{512}\)
\(3+\frac{3}{5}+\frac{3}{25}+\frac{3}{125}+\frac{3}{625}\)
\(=3\times\left(1+\frac{1}{5}+\frac{1}{25}+\frac{1}{125}+\frac{1}{625}\right)\)
\(=3\times\left(\frac{625}{625}+\frac{125}{625}+\frac{25}{625}+\frac{5}{625}+\frac{1}{625}\right)\)
\(=3\times\frac{625+125+25+5+1}{625}\)
\(=3\times\frac{781}{625}=\frac{3\times781}{625}=\frac{2343}{625}\)
\(=2\)
\(\frac{3}{3}+\frac{3}{3}=2\)