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=3/1-3/4+3/4-3/7+3/7-3/10+3/10-3/13
=1/1-1/4+1/4-1/7+1/7-1/10+1/10-1/13
=1-1/13
=12/13
3/2-3/2:(-1/8)
=3/2-3/2.(-8)
=3/2(1+8)
=3/2x9
=27/2
\(\frac{3}{2}-\frac{3}{2}:-\frac{1}{2^3}\)
\(=\frac{3}{2}-\frac{3}{2}.\frac{-2^3}{1}\)
\(=\frac{3}{2}-\left(-12\right)\)
\(=\frac{3}{2}+\frac{24}{2}\)
\(=\frac{27}{2}\)
hok tốt!!!
a,\(\frac{10x125x4x25x8}{0,8x0,04x1,25x25+0,6524+0,3476}\)
=\(\frac{10x\left(125x8\right)x\left(4x25\right)}{\left(0,8x1,25\right)x\left(0,04x25\right)+\left(0,6524+0,3476\right)}\)
=\(\frac{10x1000x100}{1x1+1}\)
=\(\frac{1000000}{2}\)=\(500000\)
b,\(\frac{3}{4}\)x X + 1,25 x X + 50% x X = 12,5 x 0,8
0,75 x X + 1,25 x X + 0,5 x X = 10
(0,75 + 1,25 + 0,5) x X = 10
2,5 x X = 10
X = 10: 2,5 =4
\(\frac{2460}{3280}=\frac{2460:820}{3280:820}=\frac{3}{4}\)
\(\frac{243240}{326840}=\frac{243240:40}{326840:40}=\frac{6081}{8171}\)
= \(\frac{\left(12344+1\right).67890-54321}{12344.67890+13569}\)
= \(\frac{12344.67890+67890-54321}{12344.67890+13569}\)
= \(\frac{12344.67890+13569}{12344.67890+13569}\)
= 1
a) 3/4x16/9-7/5:(-21/20)
=4/3-(-4/3)
=8/3
b)=7/3-1/3x[-3/2+(2/3+2)]
=7/3-1/3x[-3/2+8/3]
=7/3-1/3x7/6
=7/3-7/18
=35/18
c)=(20+37/4):9/4
=117/4:9/4
=13
d)=6-14/5x25/8-8/5:1/4
=6-35/4-32/5
=-11/4-32/5
=-183/20
3/1x4+3/4x7+...+3/97x100
=1-1/4+1/4-1/7+1/7-...+1/97-1/100
=1-1/100
=99/100
đây kô phải toán lớp 1