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=2,(6) có chu kì vì phép tính có dư
nếu đổi ra phân số là:\(\frac{8}{3}\)
a) (21x11x2x17x4)/(11x17x21x3)
=(21x11x2x17x4)/(11x17x21x3)
=8/3
b) (5x7x13x2)/(7x2x13x5x5)
=1/5
a ) 21/11 * 22/ 17 *68 / 63 = 42 /17 * 68 / 63 = 8 / 3
b) 5 / 14 * 7 / 13 * 26 / 25 = 5/ 26 * 26 / 25 = 1/ 5
\(\frac{21}{11}\cdot\frac{22}{17}\cdot\frac{68}{63}\)
\(=\frac{1}{1}\cdot\frac{2}{1}\cdot\frac{4}{3}\)
\(=\frac{8}{3}\)
a)\(\frac{21}{11}x\frac{22}{17}x\frac{68}{63}\)
=\(\frac{21x22x68}{11x17x63}\)
=\(\frac{21x11x2x17x4}{11x17x21x3}\)
=\(\frac{2x4}{3}\)
=\(\frac{8}{3}\)
b)\(\frac{5}{14}x\frac{7}{13}x\frac{26}{25}\)
=\(\frac{5x7x26}{14x13x25}\)
a) 21/11 x 22/ 17 x 68/63
= 21/1 x 2/17 x 68/63
= 21 x 8/63
= 8/3
b) 5/14 x 7/13 x 26/25
= 5/2 x 1/13 x 26/15
= 5/2 x 26/45
= 1/5
\(\frac{3}{4}\cdot\frac{15}{17}+\frac{3}{4}\cdot\frac{2}{17}+\frac{1}{17}\)
\(=\frac{3}{4}\cdot\left(\frac{15}{17}+\frac{2}{17}\right)+\frac{1}{17}\)
\(=\frac{3}{4}\cdot1+\frac{1}{17}\)
\(=\frac{5}{8}\)
\(\frac{3}{4}.\frac{15}{17}+\frac{3}{4}.\frac{2}{17}+\frac{1}{17}\)
=\(\frac{3}{4}.\left(\frac{15}{17}+\frac{2}{17}\right)+\frac{1}{17}\)
=\(\frac{3}{4}.1+\frac{1}{17}\)
=\(\frac{51}{68}+\frac{4}{68}=\frac{55}{68}\)
a) \(\frac{21\times11\times2\times17\times4}{11\times17\times21\times3}=\frac{2\times4}{3}_{ }=\frac{8}{3}\)
b)\(\frac{5\times7\times13\times2}{7\times2\times13\times5\times5}=\frac{1}{5}\)
a)\(\frac{21x22x68}{11x17x63}\) = \(\frac{1x2x4}{1x1x3}\) =\(\frac{8}{3}\)
b)\(\frac{5x7x26}{14x13x25}\) = \(\frac{1x1x2}{2x1x5}\) =\(\frac{1x1x1}{1x1x5}\) = \(\frac{1}{5}\)