Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a] 4/12 ; 5/12 ; 11/2 ; 1/4
b] 1 ; 9/12; 12/5 ; 11/3
c] 8/21; 6/11;8/7
d] 2/3 ;2/7 15/2
a]1/3 5/12 11/2 1/4
b]1 3/4 12/5 33/9
c]8/21 6/11 8/7
d]2/3 2/7 15/2
a) S
⇒ \(\dfrac{3}{5}+\dfrac{1}{4}=\dfrac{12}{20}+\dfrac{5}{20}=\dfrac{17}{20}\)
b) \(\)Đ
c) Đ
d) S
⇒ \(\dfrac{3}{4}:\dfrac{4}{9}=\dfrac{3}{4}\times\dfrac{9}{4}=\dfrac{27}{16}\)
* Mình chỉ giải thích những câu sai thôi nha
Chúc bạn học tốt
= 51/20
----------------------------------
= 3/14
------------------------------------
= 4/7 - 2/7
= 2/7
--------------------------------------
= 17/45
---------------------------------------
= 2/3
--------------------------------------
= 2 x 1/4
= 1/2
1 + 7 + 9
= 8 + 9
= 17
1 + 6 + 3 + 7
= 7 + 3 + 7
= 10 + 7
= 17
1 + 7 + 54 + 8
= 8 + 54 + 8
= 62 + 8
= 70
\(\frac{5}{7}:\frac{5}{6}-\frac{1}{3}=\frac{5}{7}:\frac{1}{2}=\frac{10}{7}\)
Đáp án là S
vì trong một phép tính có chia và trừ thì ta phải thực hiện chia trước rồi mới trừ
ủng hộ tớ nha
B) sai
C) đúng
D) sai
Bài 5
\(y+\frac{3}{4}=\frac{2}{5}+1\)
\(\Leftrightarrow y=\frac{2}{5}+1-\frac{3}{4}\)
\(\Leftrightarrow y=\frac{8}{20}+\frac{20}{20}-\frac{15}{20}\)
\(\Leftrightarrow y=\frac{13}{20}\)
B) \(\frac{2}{3}\times y=\frac{4}{9}\times\frac{3}{8}\)
\(\Leftrightarrow\frac{2}{3}y=\frac{1}{6}\)
\(\Leftrightarrow2y=\frac{1}{2}\)
\(\Leftrightarrow y=\frac{1}{4}\)
CHO XIN
7/5+4/5 7/20-1/4 5/4x3/9 7/2 : 8
=7+4/5 =7/20-5/20 =5/4x1/3 =7/2x 1/8
=11/5 =7-5/20 =5/12 =7/16
= 1/10
Nhớ tick đấy
1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)
\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)
=0
2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)
\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)
\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)
3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)
\(=\dfrac{52546}{15}\)
4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)
\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)
\(=\dfrac{4}{7}\)
1 . Đúng
2. Sai
3. Sai
4. Đúng
5. Sai
sai
sai
sai
sai
đúng