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a) \(x^2+4x+4=\left(x+2\right)^2\)
b) \(9x^2-12x+4=\left(3x-2\right)^2\)
c) \(x^2+x+\dfrac{1}{4}=\left(x+\dfrac{1}{2}\right)^2\)
a) \(x^2+4x+4=\left(x+2\right)^2\)
b) \(9x^2-12x+4=\left(3x-2\right)^2\)
c) \(x^2+x+\frac{1}{4}=\left(x+\frac{1}{2}\right)^2\)
d) kiểm tra lại đề nhé
e) \(4y^2-9x^2=\left(2x-3x\right)\left(2x+3x\right)\)
f) \(9y^2-\frac{1}{4}=\left(3y-\frac{1}{2}\right)\left(3y+\frac{1}{2}\right)\)
g) \(8x^3+8a^3=\left(2x+2a\right)\left(4x^2-4ax+4a^2\right)\)
h) \(64x^3-27y^3=\left(4x-3y\right)\left(9y^2+12xy+16x^2\right)\)
a ) \(\left(4x^2+4xy+y^2\right):\left(2x+y\right)\)
\(=\left(2x+y\right)^2:\left(2x+y\right)\)
\(=2x+y\)
b ) \(\left(27x^3+1\right):\left(3x+1\right)\)
\(=\left(3x+1\right)\left(9x^2-3x+1\right):\left(3x+1\right)\)
\(=9x^2-3x+1\)
c ) \(\left(x^2-6xy+9y^2\right):\left(3y-x\right)\)
\(=\left(x-3y\right)^2:\left(3y-x\right)\)
\(=\left(3y-x\right)^2:\left(3y-x\right)\)
\(=3y-x\)
d ) \(\left(8x^3-1\right):\left(4x^2+2x+1\right)\)
\(=\left(2x-1\right)\left(4x^2+2x+1\right):\left(4x^2+2x+1\right)\)
\(=2x-1\)
:D
\(a,=\left(x-2\right)^2-y^2=\left(x-y-2\right)\left(x+y-2\right)\\ b,=4x^2\left(x^2+2x+1\right)=4x^2\left(x+1\right)^2\\ c,=xy^2\left(x^2-2xy+y^2\right)=xy^2\left(x-y\right)^2\\ d,=\left(x-y\right)\left(x+y\right)-7\left(x-y\right)=\left(x-y\right)\left(x+y-7\right)\\ e,=\left(5x-2y\right)\left(5x+2y\right)\\ f,=x^2+3x+4x+12=\left(x+3\right)\left(x+4\right)\\ i,=x^2+2x-7x-14=\left(x+2\right)\left(x-7\right)\)
Ta có
27 x 3 – 64 y 3 = ( 3 x ) 3 – ( 4 y ) 3 = ( 3 x – 4 y ) ( ( 3 x ) 2 + 3 x . 4 y + ( 4 y ) 2 ) = ( 3 x – 4 y ) ( 9 x 2 + 12 x y + 16 )
Vậy đa thức cần điền là 9 x 2 + 12xy + 16
Đáp án cần chọn là: B
Ta có
( 27 x 3 + 27 x 2 + 9 x + 1 ) : ( 3 x + 1 ) 2 = ( 3 x + 1 ) 3 : ( 3 x + 1 ) 2 = 3 x + 1
Đáp án cần chọn là: B
a) \(\dfrac{1}{4}a^2-2a+4=\left(\dfrac{1}{2}a-2\right)^2\)
b) \(4y^2-9x^2=\left(-3x+2y\right)\left(3x+2y\right)\)
c) \(8x^3+8a^3=\left(2x+2a\right)\left(4x^2-4xa+4a^2\right)\)