Question

[Linh Phạm]

co (x+2)^2+|y-3|=0

cho hoi 'x' la nhung so nao?

giaii hoo vva giai thiich gium luon nhe, duoc cau nao hay cau do

Answer 1

[Nguyễn Huy Tú]

Ta có: \(\left\{{}\begin{matrix}\left(x+2\right)^2\ge0\\\left|y-3\right|\ge0\end{matrix}\right.\Rightarrow\left(x+2\right)^2+\left|y-3\right|\ge0\)

Mà \(\left(x+2\right)^2+\left|y-2\right|=0\)

\(\Rightarrow\left\{{}\begin{matrix}\left(x+2\right)^2=0\\\left|y-3\right|=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x+2=0\\y-3=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-2\\y=3\end{matrix}\right.\)

Vậy x = -2

Answer 2

[Linh Phạm]

quen minh hoi ca "y" la?