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\(\frac{1}{16}\)<\(\frac{1}{3\cdot4}\)tương tự=>\(\frac{1}{4}+\)\(\frac{1}{16}\)+.......+\(\frac{1}{196}< \frac{1}{3\cdot4}+......+\frac{1}{8\cdot9}=\frac{1}{3}\)--\(\frac{1}{9}\)+\(\frac{1}{4}\)=\(\frac{7}{18}< \frac{1}{2}\)
Vậy.................
8/5:(8/5.5/4) / 16/25-1/25 + 1:4/7 / (50/9-9/4).36/17) + 0,6.0,5:2/5
= 8/5:8/5:5/4 / 3/5 + 7/4 / 50/9.36/17-9/4.36/17 + 0,3.5/2
= 4/5:3/5 + 7/4 / 200/17-81/17 + 3/10.5/2
= 4/5.5/3 + 7/4 / 119/17 + 3/4
= 4/3 + 7/4 : 7 + 3/4
= 4/3 + 4 + 3/4
= 16/12 + 48/12 + 9/12
= 73/12
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1/302 < 1/301; 1/303<1/301; ...; 1/400<1/301
=> A < 1/2 + 1/301+1/301+...+1/301=1/2 + 100/301< 1/2+100/300=1/2+1/3=5/6<1
=> A<1 => đpcm
1/ Tính:
\(\frac{3}{2}-\frac{5}{6}+\frac{7}{12}-\frac{9}{20}+\frac{11}{30}-\frac{13}{42}+\frac{15}{56}-\frac{17}{72}+\frac{19}{90}\)
\(=\frac{3}{1.2}-\frac{5}{2.3}+\frac{7}{3.4}-\frac{9}{4.5}+\frac{11}{5.6}-\frac{13}{6.7}+\frac{15}{7.8}-\frac{17}{8.9}+\frac{19}{9.10}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\)
\(=1-\frac{1}{10}\)
\(=\frac{9}{10}\)
\(36.\left(\frac{1}{1}-\frac{1}{3}-\frac{1}{5}+\frac{1}{3}-\frac{1}{5}-\frac{1}{7}+...+\frac{1}{25}-\frac{1}{27}-\frac{1}{29}\right).x=\frac{4}{25}\)
Triệt tiêu còn
\(36.\left(\frac{1}{1}-\frac{1}{29}\right).x=\frac{4}{25}\)
từ đây dễ rồi, tình lần lượt rồi tìm x nhé
