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27 tháng 11 2016

\(\sqrt{a\left(a+1\right)\left(a+2\right)\left(a+4\right)\left(a+5\right)\left(a+6\right)+36}\)

\(=\sqrt{a\left(a+6\right)\left(a+1\right)\left(a+5\right)\left(a+2\right)\left(a+4\right)+36}\)

\(=\sqrt{\left(a^2+6a\right)\left(a^2+6a+5\right)\left(a^2+6a+8\right)+36}\left(1\right)\)

Đặt \(a^2+6a=x\), Ta có:

\(\left(1\right)=\sqrt{x\left(x+5\right)\left(x+8\right)+36}\)

\(=\sqrt{\left(x^2+5\right)\left(x+8\right)+36}=\sqrt{x^3+13x^2+40x+36}\)

\(=\sqrt{x^3+9x^2+4x^2+36x+4x+36}=\sqrt{\left(x+9\right)\left(x+2\right)^2}\)

Thay \(x=a^2+6a\)vào biểu thức trên ta được:

\(\sqrt{\left(a^2+6a+9\right)\left(a^2+6a+2\right)^2}=\sqrt{\left(a+3\right)^2\left(a^2+6a+2\right)^2}=\left(a+3\right)\left(a^2+6a+2\right)\)

\(\rightarrowđpcm\)

25 tháng 10 2018

\(A=\left(x-y\right)^2\left(z^2-2z+1\right)-2\left(z-1\right)\left(x-y\right)^2+\left(x-y\right)^2\)

\(A=\left(x-y\right)^2\left(z-1\right)^2-2\left(x-y\right)\left(z-1\right)\left(x-y\right)+\left(x-y\right)^2\)

\(A=\left[\left(x-y\right)\left(z-1\right)-\left(x-y\right)\right]^2\ge0\) \(\forall x,y,z\)

24 tháng 7 2016

\(A=x^4\left(y-z\right)+y^4\left(z-x\right)+z^4\left(x-y\right)\)

\(=x^4y-x^4z+y^4z-y^4x+z^4\left(x-y\right)\)

\(=xy\left(x^3-y^3\right)-z\left(x^4-y^4\right)+z^4\left(x-y\right)\)

\(=xy\left(x-y\right)\left(x^2+xy+y^2\right)-z\left(x-y\right)\left(x^3+x^2y+xy^2+y^3\right)+z^4\left(x-y\right)\)

\(=\left(x-y\right)\left[xy\left(x^2+xy+y^2\right)-z\left(x^3+x^2y+xy^2+y^3\right)+z^4\right]\)

\(=\left(x-y\right)\left(x^3y+x^2y^2+xy^3-x^3z-x^2yz-xy^2z-y^3z+z^4\right)\)

\(=\left(x-y\right)\left[x^3\left(y-z\right)+x^2y\left(y-z\right)+xy^2\left(y-z\right)-z\left(y^3-z^3\right)\right]\)

\(=\left(x-y\right)\left[x^3\left(y-z\right)+x^2y\left(y-z\right)+xy^2\left(y-z\right)-z\left(y-z\right)\left(y^2+yz+z^2\right)\right]\)

\(=\left(x-y\right)\left(y-z\right)\left[x^3+x^2y+xy^2-z\left(y^2+yz+z^2\right)\right]\)

\(=\left(x-y\right)\left(y-z\right)\left(x^3+x^2y+xy^2-y^2z-yz^2-z^3\right)\)

\(=\left(x-y\right)\left(y-z\right)\left[x^3-z^3+y\left(x^2-z^2\right)+y^2\left(x-z\right)\right]\)

\(=\left(x-y\right)\left(y-z\right)\left[\left(x-z\right)\left(x^2+xz+z^2\right)+y\left(x-z\right)\left(x+z\right)+y^2\left(x-z\right)\right]\)

\(=\left(x-y\right)\left(y-z\right)\left(x-z\right)\left[x^2+xz+z^2+y\left(x+z\right)+y^2\right]\)

\(=\left(x-y\right)\left(y-z\right)\left(x-z\right)\frac{2\left(x^2+xz+z^2+xy+yz+y^2\right)}{2}\)

\(=\left(x-y\right)\left(y-z\right)\left(x-z\right)\frac{x^2+2xz+z^2+x^2+xy+y^2+y^2+yz+z^2}{2}\)

\(\left(x-y\right)\left(y-z\right)\left(x-z\right)\frac{\left(x+z\right)^2+\left(x+y\right)^2+\left(y+z\right)^2}{2}\)

\(Ta\)\(có\)\(x>y>z\Rightarrow\left(x-y\right);\left(y-z\right);\left(x-z\right)>0\)

                 \(\left(x+z\right)^2;\left(y+z\right)^2;\left(x+y\right)^2\ge0\)

\(\Rightarrow A>o\Rightarrow A\)\(luôn\)\(dương\)

5 tháng 10 2021

a) Sửa đề: \(A=\left(3x-2\right)\left(9x^2+6x+4\right)-3x\left(9x^2-2\right)\)

\(=27x^3-8-27x^3+6=-2\)

b: Ta có: \(B=\left(3x+5\right)^2+\left(6x+10\right)\left(2-3x\right)+\left(2-3x\right)^2\)

\(=\left(3x+5+2-3x\right)^2\)

=49

14 tháng 8 2021

A = (2x+3)(4x2−6x+9)−2(4x3−1)−36

=8x3-12x2+18x+12x2-18x+27-8x3+2-36

=-7

Ta có: \(A=\left(2x+3\right)\left(4x^2-6x+9\right)-2\left(4x^3-1\right)-36\)

\(=8x^3+27-8x^3+2-36\)

\(=-7\)

5 tháng 10 2021

\(A=x^2-16-6x-2x^2+x^2+6x+9=-7\\ B=\left(x^2+4\right)\left(x^2-4\right)-x^4+9\\ B=x^4-16-x^4+9=-7\)

5 tháng 10 2021

a) \(A=\left(x+4\right)\left(x-4\right)-2x\left(3+x\right)+\left(x+3\right)^2\)

\(=x^2-16-2x^2-6x+x^2+6x+9=-7\)

b) \(B=\left(x^2+4\right)\left(x+2\right)\left(x-2\right)-\left(x^2+3\right)\left(x^2-3\right)\)

\(=\left(x^2+4\right)\left(x^2-4\right)-\left(x^4-9\right)\)

\(=x^4-16-x^4+9=-7\)