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ta có:
\(\frac{a_1}{a_2}=\frac{a_2}{a_3}=...=\frac{a_{2008}}{a_{2009}}=\frac{a_1+a_2+...+a_{2008}}{a_2+a_3+...+a_{2009}}\)
=>\(\left(\frac{a_1}{a_2}\right)^{2008}=\left(\frac{a_2}{a_3}\right)^{2008}=....=\left(\frac{a_{2008}}{a_{2009}}\right)=\left(\frac{a_1+a_2+..+a_{2008}}{a_2+a_3+..+a_{2009}}\right)^{2008}\)
\(=\frac{a_1a_2}{a_2a_3}=...=\frac{a_{2009}}{a_{2009}}=\frac{a_1}{a_{2009}}\)
=>\(\frac{a_1}{a_{2009}}=\left(....\right)\) (đpcm)
Có: \(\frac{a_1}{a_2}=\frac{a_2}{a_3}=\frac{a_3}{a_4}=.....=\frac{a_{2008}}{a_{2009}}=\frac{a_1+a_2+a_3+...+a_{2008}}{a_2+a_3+a_4+....+a_{2009}}\)(tính chất dãy tỉ số bằng nhau)
=> \(\left(\frac{a_1}{a_2}\right)^{2008}=\left(\frac{a_2}{a_3}\right)^{2008}=...=\left(\frac{a_{2008}}{a_{2009}}\right)^{2008}=\left(\frac{a_1+a_2+...+a_{2008}}{a_2+a_3+...+a_{2009}}\right)^{2008}\)
\(=\frac{a_1.a_2.....a_{2008}}{a_2.a_3.....a_{2009}}=\frac{a_1}{a_{2009}}\)
=> \(\frac{a_1}{a_{2009}}=\left(\frac{a_1+a_2+...+a_{2008}}{a_2+a_3+....+a_{2009}}\right)^{2008}\)
=> Đpcm
Ta có:
\(\frac{a1}{a2}=\frac{a2}{a3}=\frac{a3}{a4}=...=\frac{a2008}{a2009}=\frac{\left(a1+a2+...+a2008\right)}{\left(a2+a3+...+a2009\right)}\)
\(\Rightarrow\left(\frac{a1}{a2}\right)^{2008}=\left(\frac{a2}{a3}\right)^{2008}=..=\left(\frac{a2008}{a2009}\right)^{2008}=\left(\frac{a1+a2+..+a2008}{a2+a3+..+a2009}\right)^{2008}\)
\(\Rightarrow\frac{a1.a2....a2008}{a2.a3...a2009}=\left(\frac{a1+a2+..+a2008}{a2+a3+..+a2009}\right)^{2008}\)
\(\Rightarrow\frac{a1}{a2009}=\left(\frac{a1+a2+..+a2008}{a2+a3+..+a2009}\right)^{2008}\)
Ta có \(\frac{a_1}{a_2}=\frac{a_2}{a_3}=\frac{a_3}{a_4}=...=\frac{a_{2020}}{a_{2021}}=\frac{a_1+a_2+a_3+...+a_{2020}}{a_2+a_3+a_4+...+a_{2021}}\)(dãy tỉ só bằng nhau)
=> \(\frac{a_1}{a_2}=\frac{a_1+a_2+a_3+...+a_{2020}}{a_2+a_3+a_4+...+a_{2021}}\)
<=> \(\left(\frac{a_1}{a_2}\right)^{2020}=\left(\frac{a_1+a_2+a_3+...+a_{2020}}{a_2+a_3+a_4+...+a_{2021}}\right)^{2020}\)
<=> \(\frac{a_1}{a_2}.\frac{a_1}{a_2}.\frac{a_1}{a_2}...\frac{a_1}{a_2}=\left(\frac{a_1+a_2+a_3+...+a_{2020}}{a_2+a_3+a_4+...+a_{2021}}\right)^{2020}\)
<=> \(\frac{a_1}{a_2}.\frac{a_2}{a_3}.\frac{a_3}{a_4}...\frac{a_{2020}}{a_{2021}}=\left(\frac{a_1+a_2+a_3+...+a_{2020}}{a_2+a_3+a_4+...+a_{2021}}\right)^{2020}\)
<=> \(\frac{a_1}{a_{2021}}=\left(\frac{a_1+a_2+a_3+...+a_{2020}}{a_2+a_3+a_4+...+a_{2021}}\right)^{2020}\)
\(\frac{a_1}{a_2}=\frac{a_2}{a_3}=\frac{a_3}{a_4}=...=\frac{a_{2003}}{a_{2004}}=\frac{a_1+a_2+a_3+...+a_{2003}}{a_2+a_3+a_4+...+a_{2004}}\)
số các phân số trong dãy là:
(2003-1):1+1=2003(phân số)
\(\Rightarrow\frac{a_1}{a_2}.\frac{a_2}{a_3}.\frac{a_3}{a_4}...\frac{a_{2003}}{a_{2004}}=\frac{a_1}{a_{2004}}=\left(\frac{a_1+a_2+a_3+...+a_{2003}}{a_2+a_3+a_4+...+a_{2004}}\right)^{2003}\)
=>đpcm
\(\frac{a_1}{a_2}=\frac{a_2}{a_3}=\frac{a_3}{a_4}=...=\frac{a_{2003}}{a_{2004}}=\frac{a_1+a_2+a_3+...+a_{2003}}{a_2+a_3+a_4+...+a_{2004}}\)
số các phân số trong dãy là:(2003-1):1+1=2003(phân số)