Question

[PiinSuThien11]

 \(ChoE=\frac{100^2+1^2}{100.1}+\frac{99^2+2^2}{99.2}+\frac{98^2+3^2}{98.3}+...+\frac{52^2+49^2}{52.49}+\frac{51^2+50^2}{51.50}\)

\(ChoF=\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100}+\frac{1}{101}\)

\(ChoG=\frac{1}{100.1}+\frac{1}{99.2}+\frac{1}{98.3}+...+\frac{1}{52.49}+\frac{1}{51.50}\)

\(a.Tính:\frac{E}{F}\)                                                                  \(b.Tính:F-101G\)