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bài giải :
a, nếu mỗi toa xe chở 20 tấn hàng thì ta cần số toa xe là: 180: 20 = 9 (toa )
b, nếu mỗi toa chở 30 tấn hàng thì cần số toa xe là : 180 :30 = 6 (toa )
đáp số : a: 9 toa
b, 6 toa
đúng không ???
b: =45/8+1/2=45/8+4/8=49/8
c: =7/2-1/20=70/20-1/20=69/20
d: =5/4+3/10=25/20+6/20=31/20
a: 1-1/2=1/2
b: 1-3/10=7/10
c:3-1/3=8/3
d: 4-1/9=35/9
e: 8-2/3=22/3
f: 5-2/5=23/5
a: bằng 1 phần 2
b: bằng 7 phần 10
c: bằng 2 phần 3
d:bằng 35 phần 9
e: bằng 22 phần 3
g: bằng 23 phần 5
chúc bn học tốt
a: \(\dfrac{5}{3}\cdot\dfrac{4}{5}=\dfrac{4}{3}\)
b: \(\dfrac{2}{3}\cdot\dfrac{3}{5}=\dfrac{2}{5}\)
c: \(\dfrac{7}{6}\cdot\dfrac{6}{5}=\dfrac{7}{5}\)
d: \(\dfrac{8}{5}\cdot\dfrac{5}{7}=\dfrac{8}{7}\)
e: \(\dfrac{7}{6}\cdot\dfrac{6}{7}=\dfrac{7}{7}=1\)
g: \(\dfrac{9}{5}\cdot\dfrac{5}{2}=\dfrac{9}{2}\)
h: \(\dfrac{4}{3}\cdot\dfrac{3}{5}=\dfrac{4}{5}\)
\(a,\dfrac{13}{4}\times\dfrac{2}{3}\times\dfrac{4}{13}\times\dfrac{3}{2}=\left(\dfrac{13}{4}\times\dfrac{4}{3}\right)\times\left(\dfrac{2}{3}\times\dfrac{3}{2}\right)=1\times1=1\)
\(b,\dfrac{75}{100}+\dfrac{18}{21}+\dfrac{19}{32}+\dfrac{1}{4}+\dfrac{3}{21}+\dfrac{13}{32}=\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\left(\dfrac{18}{21}+\dfrac{3}{21}\right)+\left(\dfrac{19}{32}+\dfrac{13}{32}\right)=1+1+1=3\\ c,\dfrac{4}{7}\times\dfrac{5}{6}+\dfrac{4}{7}\times\dfrac{1}{6}=\dfrac{4}{7}\times\left(\dfrac{5}{6}+\dfrac{1}{6}\right)=\dfrac{4}{7}\times1=\dfrac{4}{7}\\ d,\dfrac{3}{5}\times\dfrac{7}{9}-\dfrac{3}{5}\times\dfrac{2}{9}=\dfrac{3}{5}\times\left(\dfrac{7}{9}-\dfrac{2}{9}\right)=\dfrac{3}{5}\times\dfrac{5}{9}=\dfrac{1}{3}\)
\(e,\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{3}{12}=\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{1}{4}=\dfrac{1}{4}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)=\dfrac{1}{4}\times1=\dfrac{1}{4}\\ f,\dfrac{7}{9}\times\dfrac{8}{5}\times\dfrac{3}{5}=\dfrac{56}{75}\\ g,\dfrac{2}{5}\times\dfrac{3}{4}+\dfrac{3}{4}\times\dfrac{3}{5}=\dfrac{3}{4}\times\left(\dfrac{2}{5}+\dfrac{3}{5}\right)=\dfrac{3}{4}\times1=\dfrac{3}{4}\\ h,\dfrac{2006}{2005}\times\dfrac{3}{4}-\dfrac{3}{4}\times\dfrac{1}{2005}=\dfrac{3}{4}\times\left(\dfrac{2006}{2005}-\dfrac{1}{2005}\right)=\dfrac{3}{4}\times1=\dfrac{3}{4}\)
a: \(=\dfrac{13}{4}\cdot\dfrac{4}{13}\cdot\dfrac{2}{3}\cdot\dfrac{3}{2}=1\cdot1=1\)
b: \(=\dfrac{3}{4}+\dfrac{1}{4}+\dfrac{6}{7}+\dfrac{1}{7}+\dfrac{19}{32}+\dfrac{13}{32}=1+1+1=3\)
c: \(=\dfrac{4}{7}\left(\dfrac{5}{6}+\dfrac{1}{6}\right)=\dfrac{4}{7}\)
d: \(=\dfrac{3}{5}\left(\dfrac{7}{9}-\dfrac{2}{9}\right)=\dfrac{3}{5}\cdot\dfrac{5}{9}=\dfrac{1}{3}\)
e: \(=\dfrac{1}{4}\left(\dfrac{5}{9}+\dfrac{4}{9}\right)=\dfrac{1}{4}\)
a:\(\dfrac{33}{44}=\dfrac{3}{4}\\ MSC:8\\ \dfrac{3}{4}=\dfrac{3\times2}{4\times2}=\dfrac{6}{8};\dfrac{2}{8}\)
b:\(\dfrac{9}{12}=\dfrac{3}{4};\dfrac{24}{36}=\dfrac{7}{9}\\ MSC:72\\ \dfrac{3}{4}=\dfrac{3\times18}{4\times18}=\dfrac{54}{72};\dfrac{7}{9}=\dfrac{7\times8}{9\times8}=\dfrac{56}{72};\dfrac{3}{8}=\dfrac{3\times9}{8\times9}=\dfrac{27}{72}\)
mong có ai giúp