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\(\dfrac{4}{9}=\dfrac{44}{99};\dfrac{5}{11}=\dfrac{45}{99};\dfrac{44}{99}< \dfrac{45}{99}\Rightarrow\dfrac{4}{9}< \dfrac{5}{11}\\ \dfrac{2}{3}=\dfrac{8}{12}< \dfrac{11}{2}\\ \dfrac{7}{18}>\dfrac{7}{24}\left(18< 24\right)\\ \dfrac{12}{13}=\dfrac{12\cdot101}{13\cdot101}=\dfrac{1212}{1313}>\dfrac{1010}{1313}\\ \dfrac{2}{5}=\dfrac{2\cdot11}{5\cdot11}=\dfrac{22}{55}\\ \dfrac{6}{7}< 1< \dfrac{7}{6}\)
a)\(\frac{4}{3.7}+\frac{4}{7.11}+...+\frac{4}{23.27}=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{23}-\frac{1}{27}=\frac{1}{3}-\frac{1}{27}=\frac{8}{27}\)
b)\(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{6.7}=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{6}-\frac{1}{7}=\frac{1}{2}-\frac{1}{7}=\frac{5}{14}\)
c)\(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{11.13}+\frac{2}{1.2}+\frac{2}{2.3}+...+\frac{2}{9.10}=\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{11}-\frac{1}{13}\right)+2\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right)\)
\(=\frac{1}{3}-\frac{1}{13}+2\left(1-\frac{1}{10}\right)=\frac{10}{39}+\frac{9}{5}=\frac{401}{195}\)
viết rõ lại cái đề giùm tui tui mới làm được
1 - 2 + 3 - 4 + 5 - 6 + 7 - 8 + 9 - 10 + 11
= ( - 1 ) + ( - 1 ) + ( - 1 ) + ( - 1 ) + ( - 1 ) + 11
= 6
Hok tốt
\(\frac{5}{6}+\frac{7}{4}+\frac{11}{24}=\frac{20+42+11}{24}=\frac{73}{24}\)
\(\frac{5}{7}-\frac{2}{5}-\frac{3}{35}=\frac{25-14-3}{35}=\frac{8}{35}\)
\(\frac{4}{9}\times\frac{3}{2}\times\frac{9}{5}=\frac{4\times3\times9}{9\times2\times5}=\frac{6}{5}\)
\(\frac{21}{22}:\frac{7}{11}\times\frac{2}{3}=\frac{21}{22}\times\frac{11}{7}\times\frac{2}{3}=\frac{3}{2}\times\frac{2}{3}=1\)