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a, 48 . 19 + 81 . 48
= 48 . (19 + 81)
= 48 . 100 = 4800
b, 74 : 72 + [ 62 - (102 - 4 . 16)]
= 72 + [36 - (100 - 64)]
= 49 + [36 - 36]
= 49
x, (-115) + (-40) + 115 + |-35|
= [(-115) + 115] + (-40) + 35
= 0 + (-5) = -5
a, 48 . 19 + 81 . 48
= 48 . ( 19 + 81 )
= 48 . 100
= 4800
b,74 : 72 + [ 62 - (102 - 4 . 16)]
= 49 + [ 36 - ( 100 - 4 . 16 )]
= 49 + [ 36 - 36 ]
= 49 + 0
= 49
c,( -115 ) + ( -40 ) + 115 + | -35 |
= [(-115) + 115 ] + (-40) + 35
= 0 + (-40 ) + 35
= -5
HỌC TỐT !
a) \(1-\dfrac{1}{2}+\dfrac{1}{3}=\dfrac{6}{6}-\dfrac{3}{6}+\dfrac{2}{6}=\dfrac{6-3+2}{6}=\dfrac{1}{6}\)
\(b.\) \(\dfrac{2}{5}+\dfrac{3}{5}:\dfrac{9}{10}=\dfrac{2}{5}+\dfrac{3}{5}.\dfrac{10}{9}=\dfrac{2}{5}+\dfrac{2}{3}=\dfrac{6}{15}+\dfrac{10}{15}=\dfrac{6+10}{15}=\dfrac{16}{15}\)
\(c.\) \(\dfrac{7}{11}.\dfrac{3}{4}+\dfrac{7}{11}.\dfrac{1}{4}+\dfrac{4}{11}=\dfrac{21}{44}+\dfrac{7}{44}+\dfrac{4}{11}=\dfrac{21}{44}+\dfrac{7}{44}+\dfrac{16}{44}=\dfrac{21+7+16}{44}=\dfrac{44}{44}=1\)
a/\(1-\dfrac{1}{2}+\dfrac{1}{3}=\dfrac{6}{6}-\dfrac{3}{6}+\dfrac{2}{6}=\dfrac{5}{6}\)
b/\(\dfrac{2}{5}+\dfrac{3}{5}:\dfrac{9}{10}=\dfrac{2}{5}+\dfrac{3}{5}.\dfrac{10}{9}=\dfrac{2}{5}+\dfrac{2}{3}=\dfrac{6}{15}+\dfrac{10}{15}=\dfrac{16}{15}\)
Bài 2:
Ta có: \(16x+40=10\cdot3^2+5\left(1+2+3\right)\)
\(\Leftrightarrow16x+40=90+30\)
\(\Leftrightarrow16x=80\)
hay x=5
35:7
4:
a: =4/15-2,9+11/15=1-2,9=-1,9
b: \(=-36,75+3,7-63,25+6,3=10-100=-90\)
c: \(=6,5+3,5-\dfrac{10}{17}-\dfrac{7}{17}=10-1=9\)
d: \(=\dfrac{13}{25}\left(-39,1-60,9\right)=\dfrac{13}{25}\left(-100\right)=-52\)
e: =-5/12-7/12-3,7-6,3=-1-10=-11
f: =2,8(-6/13-7/13)-7,2=-2,8-7,2=-10
a) \(48\cdot19+81\cdot48\)
\(=48\cdot\left(19+81\right)\)
\(=49\cdot100\)
\(=4900\)
a,48.19+81.48
=48.(19+81)
=48.100
=48000
hok tốt