Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
tham khảo
uses crt;
var st:string;
i,d:integer;
begin
clrscr;
readln(st);
d:=length(st);
for i:=1 to d do
if (not (st[i] in ['A'..'Z'])) and (not (st[i] in ['a'..'z'])) then write(st[i]);
readln;
end.
Bài 1:
uses crt;
var S:String;
vt:integer;
begin
clrscr;
Write(‘Nhap 1 xau:’); Readln(S);
While pos(‘nang’,s)>0 do
Begin
Vt:= pos(‘nang’,s);
Delete(s,vt,4);
Insert(‘mua’,s ,vt);
End;
Writeln(‘Xau sau khi thay the ’,s);
Readln;
End.
Bài 2:
uses crt;
var st:string;
d,i,kt:integer;
begin
clrscr;
write('Nhap xau:'); readln(st);
d:=length(st);
kt:=0;
for i:=1 to d do
if st[i]<>st[d-i+1] then kt:=1;
if kt=0 then writeln(st,' la xau doi xung')
else writeln(st,' khong la xau doi xung');
readln;
end.
2:
uses crt;
var st:string;
d,i,dem1,dem2:integer;
begin
clrscr;
write('Nhap xau:'); readln(st);
d:=length(st);
dem1:=0;
dem2:=0;
for i:=1 to d do
begin
if st[i] in ['0'..'9'] then inc(dem1);
if (st[i] in ['a'..'z']) or (st[i] in ['A'..'Z']) then inc(dem2);
end;
writeln('So ki tu la chu so la: ',dem1);
writeln('So ki tu la chu cai la: ',dem2);
for i:=1 to d do
if st[i] in ['0'..'9'] then delete(st,i,1);
writeln('Xau sau khi xoa cac chu so la: ',st);
readln;
end.
Program HOC24;
var s: string;
i: byte;
begin
write('Nhap xau :'); readln(s);
for i:=1 to length(s) do if s[i]<>'a' then write(s[i]);
readln
end.
uses crt;
var st:string;
i,d:integer;
begin
clrscr;
write('Nhap xau:'); readln(st);
d:=length(st);
for i:=1 to d do
if st[i]='a' then delete(st,i,1);
writeln(st);
readln;
end.
uses crt;
var st:string;
dem,i,d:integer;
begin
clrscr;
readln(st);
dem:=0;
d:=length(st);
for i:=1 to d do
if st[i]=' ' then inc(dem);
write(dem);
readln;
end.
Program HOC24;
var s: string;
x: char;
d: byte;
begin
write('Nhap xau: '); readln(s);
write('Nhap ki tu: '); readln(x);
d:=0;
for i:=1 to length(s) do if s[i]=x then d:=d+1;
if d=0 then write('Ki tu do khong xuat hien trong xau') else write('Ki tu do xuat hien trong xau');
readln
end.
uses crt;
var st:string;
i,d:integer;
begin
clrscr;
readln(st);
d:=length(st);
for i:=1 to d do
if (not (st[i] in ['A'..'Z'])) and (not (st[i] in ['a'..'z'])) then write(st[i]);
readln;
end.