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Ta có :
1/1.4+1/4.7+...+1/91.94
=1/3.(1/1-1/4+...+1/91-1/94)
=1/3.(1/1-1/94)
=1/3.93/94
=31/94
Ta có :
1/1.4+1/4.7+...+1/91.94
=1/3.(1/1-1/4+...+1/91-1/94)
=1/3.(1/1-1/94)
=1/3.93/94
=31/94
Tính nhanh
a) 5/1x3 + 5/3x5 + 5/5x7 + ........ + 5/43x45
b) 6/1x4 + 6/4x7 + 6/7x10 + ...... + 6/97x100
\(a,\frac{5}{1.3}+\frac{5}{3.5}+\frac{5}{5.7}+...+\frac{5}{43.45}=\frac{5}{2}\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{43.45}\right)=\frac{5}{3}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{43}-\frac{1}{45}\right)=\frac{5}{3}.\frac{44}{45}=\frac{44}{27}\)
\(A=\frac{1}{1.4}+\frac{1}{4.7}+.....+\frac{1}{97.100}\)
\(3A=\frac{3}{1.4}+\frac{3}{4.7}+......+\frac{3}{97.100}\)
\(3A=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+.......+\frac{1}{97}-\frac{1}{100}\)
\(3A=1-\frac{1}{100}\)
\(3A=\frac{99}{100}\)
\(A=\frac{99}{100}:3\)
\(A=\frac{33}{100}\)
A=1/1x4+1/4x7+.....+1/97x100
A=1x3/1x4x3+1x3/4x7x3+....+1x3/97x100x3
A=1/3x(3/1x4+3/4x7+...+3/97x100)
A=1/3x(1-1/4+1/4-1/7+.....+1/97-1/100)
A=1/3x(1-1/100)
A=1/3x99/100
A=33/100