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\(\frac{1}{2}x+\frac{1}{5}x+\frac{3}{5}=0\)
=> \(\left(\frac{1}{2}+\frac{1}{5}\right)x+\frac{3}{5}=0\)
=> \(\frac{7}{10}x+\frac{3}{5}=0\)
=> \(\frac{7}{10}x=-\frac{3}{5}\)
=> \(x=\left(-\frac{3}{5}\right):\frac{7}{10}=\left(-\frac{3}{5}\right)\cdot\frac{10}{7}=\left(-\frac{3}{1}\right)\cdot\frac{2}{7}=-\frac{6}{7}\)
b) \(\left|2\frac{1}{2}+x\right|-\left(-\frac{2}{3}\right)=3\)
=> \(\left|\frac{5}{2}+x\right|+\frac{2}{3}=3\)
=> \(\left|\frac{5}{2}+x\right|=\frac{7}{3}\)
=> \(\orbr{\begin{cases}\frac{5}{2}+x=\frac{7}{3}\\\frac{5}{2}+x=-\frac{7}{3}\end{cases}}\Rightarrow\orbr{\begin{cases}x=-\frac{1}{6}\\x=-\frac{29}{6}\end{cases}}\)
c) \(\left|x+\frac{4}{15}\right|-\left|-3.75\right|=-\left|-2,15\right|\)
=> \(\left|x+\frac{4}{15}\right|-3,75=-2,15\)
=> \(\left|x+\frac{4}{15}\right|=\frac{8}{5}\)
=> \(\orbr{\begin{cases}x+\frac{4}{15}=\frac{8}{5}\\x+\frac{4}{15}=-\frac{8}{5}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{4}{3}\\x=-\frac{28}{15}\end{cases}}\)
a, \(\frac{1}{2}x+\frac{1}{5}x+\frac{3}{5}=0\Leftrightarrow\frac{7}{10}x+\frac{3}{5}=0\Leftrightarrow x=-\frac{6}{7}\)
b, đề sai
c, \(\left|\frac{x+4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\Leftrightarrow\frac{x+4}{15}-3,75=-2,15\Leftrightarrow\frac{x+4}{15}=\frac{8}{5}\Leftrightarrow x+4=24\Leftrightarrow x=28\)
\(\text{a)4,38-19+0,62}\)\(=-14\)
\(b.3,45-5,7+8,55=6,3\)
\(c.14,7+\left(-8,4\right)+\left(-4,7\right)=1.6\)
2.
\(a,-2,4-\left(0,54-2,5\right)=-0,44\)
\(b,-25,4-\left(5,54-2,5\right)=-28,44\)
\(c.2,15-\left(-0,6+0,12\right)=2.63\)
1: \(\Leftrightarrow2x-1\in\left\{1;-1;2;-2;3;-3;4;-4;6;-6;8;-8;12;-12;24;-24\right\}\)
=>\(x\in\left\{1;0;\dfrac{3}{2};-\dfrac{1}{2};2;-1;\dfrac{5}{2};-\dfrac{3}{2};\dfrac{7}{2};-\dfrac{5}{2};\dfrac{9}{2};-\dfrac{7}{2};\dfrac{13}{2};-\dfrac{11}{2};\dfrac{25}{2};-\dfrac{23}{2}\right\}\)
2: =>x+6+9 chia hết cho x+6
=>\(x+6\in\left\{1;-1;3;-3;9;-9\right\}\)
hay \(x\in\left\{-5;-7;-3;-9;3;-15\right\}\)
3: =>2x+4+15 chia hét cho x+2
=>\(x+2\in\left\{1;-1;3;-3;5;-5;15;-15\right\}\)
=>\(x\in\left\{-1;-3;1;-5;3;-7;13;-17\right\}\)
a) | 5/4x -7/2| - | 5/8x + 3/5| = 0
|5/4x - 7/2| = | 5/8x + 3/5|
TH1: 5/4x - 7/2 = 5/8x + 3/5
=> 5/4x - 5/8x = 3/5 +7/2
5/8x = 41/10
x = 41/10:5/8
x = 164/25
TH2: 5/4x - 7/2 = -5/8x - 3/5
=> 5/4x + 5/8x = -3/5 +7/2
15/8x = 29/10
x = 29/10 : 15/8
x = 116/75
KL: x = 164/25 hoặc x = 116/75
các bài cn lại b lm tương tự nha! h lm dài lắm!
a ) x = − 3 4 + 4 5 ⇔ x = 1 20 b ) x = − 4 9 : 2 , 5 ⇔ x = − 8 45 c ) 3 , 5 − 2 x = 1 7 : 2 3 7 ⇔ 3 , 5 − 2 x = 1 17 ⇔ 2 x = 3 , 5 − 1 17 ⇔ 2 x = 117 34 ⇔ x = 117 34 : 2 = 117 68
a) \(\left(\frac{2x}{5}-1\right):\left(-5\right)=\frac{1}{7}\)
\(\frac{2x}{5}-1=\frac{1}{7}.\left(-5\right)\)
\(\frac{2x}{5}-1=\frac{-5}{7}\)
\(\frac{2x}{5}=\frac{-5}{7}+\frac{7}{7}\)
\(\frac{2x}{5}=\frac{2}{7}\)
\(=>2x.7=2.5\)
\(=>14x=10\)
\(=>x=\frac{5}{7}\)
c) \(\left|3,5+2,5x\right|-2,5=3,5\)
\(\left|3,5+2,5x\right|=3,5+2,5\)
\(\left|3,5+2,5x\right|=6\)
\(TH1\) \(3,5+2,5x=6\) \(TH2\) \(3,5+2,5x=-6\)
\(2,5x=6-3,5\) \(2,5x=-6-3,5\)
\(2,5x=2,5\) \(2,5x=-9.5\)
\(x=1\) \(x=-3,8\)
vậy \(x=1\) hoặc \(x=-3,8\)
câu d) làm tương tự như câu c)
a) \(\left|2x\right|-\left|-2,5\right|=\left|-7,5\right|\)
\(\Leftrightarrow\left|2x\right|-2,5=7,5\)
\(\Leftrightarrow\left|2x\right|=10\)
\(\Leftrightarrow\begin{cases}x\ge0\\2x=10\end{cases}\) hoặc \(\begin{cases}x< 0\\2x=-10\end{cases}\)
\(\Leftrightarrow\begin{cases}x\ge0\\x=5\left(tm\right)\end{cases}\) hoặc \(\begin{cases}x< 0\\x=-5\left(tm\right)\end{cases}\)
Vậy x={5;-5}
b)\(\left|3x\right|\cdot\left|-3,5\right|=\left|-2,8\right|\)
\(\Leftrightarrow\left|3x\right|\cdot3,5=2,8\)
\(\Leftrightarrow\left|3x\right|=\frac{4}{5}\)
\(\Leftrightarrow\begin{cases}x\ge0\\3x=\frac{4}{5}\end{cases}\) hoặc \(\begin{cases}x< 0\\3x=-\frac{4}{5}\end{cases}\)
\(\Leftrightarrow\begin{cases}x\ge0\\x=\frac{4}{15}\end{cases}\) hoặc \(\begin{cases}x< 0\\x=-\frac{4}{15}\end{cases}\)
Vậy x={4/15;-4/15}
c) \(\left(3x-5\right)\left(\frac{3}{2}x+2\right)\left(0,5x-10\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}3x-5=0\\\frac{3}{2}x+2=0\\0,5x-10=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=\frac{5}{3}\\x=-\frac{4}{3}\\x=20\end{array}\right.\)
a)|2x|-|-2,5|=|-7,5|
|2x|-2,5=7,5
|2x|=10
\(\Rightarrow\left[\begin{array}{nghiempt}2x=10\\2x=-10\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=5\\x=-5\end{array}\right.\)
Vậy x=5;-5
`2,15-x=3,05`
`x=2,15-3,05`
`x=-0,9`
Vậy `x=-0,9`
__________________
`0,12-(2x-5)=1,88`
`2x-5=0,12-1,88`
`2x-5=-1,76`
`2x=-1,76+5`
`2x=3,24`
`x=3,24:2`
`x=1,62`
Vậy `x=1,62`
__________________
`1,74-3,5:x=1,24`
`3,5:x=1,74-1,24`
`3,5:x=0,5`
`x=3,5:0,5`
`x=7`
Vậy `x=7`
2,15−x=3,052,15-x=3,05
x=2,15−3,05x=2,15-3,05
x=−0,9x=-0,9
Vậy x=−0,9x=-0,9
__________________
0,12−(2x−5)=1,880,12-(2x-5)=1,88
2x−5=0,12−1,882x-5=0,12-1,88
2x−5=−1,762x-5=-1,76
2x=−1,76+52x=-1,76+5
2x=3,242x=3,24
x=3,24:2x=3,24:2
x=1,62x=1,62
Vậy x=1,62x=1,62
__________________
1,74−3,5:x=1,241,74-3,5:x=1,24
3,5:x=1,74−1,243,5:x=1,74-1,24
3,5:x=0,53,5:x=0,5
x=3,5:0,5x=3,5:0,5
x=7x=7
Vậy x=7