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* Trả lời:
\(\left(1\right)\) \(-3\left(1-2x\right)-4\left(1+3x\right)=-5x+5\)
\(\Leftrightarrow-3+6x-4-12x=-5x+5\)
\(\Leftrightarrow6x-12x+5x=3+4+5\)
\(\Leftrightarrow x=12\)
\(\left(2\right)\) \(3\left(2x-5\right)-6\left(1-4x\right)=-3x+7\)
\(\Leftrightarrow6x-15-6+24x=-3x+7\)
\(\Leftrightarrow6x+24x+3x=15+6+7\)
\(\Leftrightarrow33x=28\)
\(\Leftrightarrow x=\dfrac{28}{33}\)
\(\left(3\right)\) \(\left(1-3x\right)-2\left(3x-6\right)=-4x-5\)
\(\Leftrightarrow1-3x-6x+12=-4x-5\)
\(\Leftrightarrow-3x-6x+4x=-1-12-5\)
\(\Leftrightarrow-5x=-18\)
\(\Leftrightarrow x=\dfrac{18}{5}\)
\(\left(4\right)\) \(x\left(4x-3\right)-2x\left(2x-1\right)=5x-7\)
\(\Leftrightarrow4x^2-3x-4x^2+2x=5x-7\)
\(\Leftrightarrow-x-5x=-7\)
\(\Leftrightarrow-6x=-7\)
\(\Leftrightarrow x=\dfrac{7}{6}\)
\(\left(5\right)\) \(3x\left(2x-1\right)-6x\left(x+2\right)=-3x+4\)
\(\Leftrightarrow6x^2-3x-6x^2-12x=-3x+4\)
\(\Leftrightarrow-15x+3x=4\)
\(\Leftrightarrow-12x=4\)
\(\Leftrightarrow x=-\dfrac{1}{3}\)
Noob ơi, bạn phải đưa vào máy tính ý solve cái là ra x luôn, chỉ tội là đợi hơi lâu
a, 4.(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14)
=> 72 - 20x - 36x + 84 = 30x - 240 - 6x - 84
=> (72 + 84) + (-20x - 36x) = (30x - 6x) + (-240 - 84)
=> 156 - 56x = 24x - 324
=> 24x + 56x = 324 + 156
=> 80x = 480
=> x = 480 : 80 = 6
Vậy x = 6
1: Trường hợp 1: x<-2
Pt sẽ là -x-2+5-x=7
=>-2x+3=7
=>-2x=4
hay x=-2(loại)
Trường hợp 2: -2<=x<5
Pt sẽlà x+2+5-x=7
=>7=7(luôn đúng)
Trường hợp 3: x>=5
Pt sẽ là x+2+x-5=7
=>2x-3=7
=>x=5(nhận)
4: \(\left|x^2-2x\right|=x\)
\(\Leftrightarrow\left\{{}\begin{matrix}x>=0\\\left(x^2-2x\right)^2=x^2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x\ge0\\\left(x^2-2x-x\right)\left(x^2-2x+x\right)=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x\ge0\\\left(x^2-3x\right)\left(x^2-x\right)=0\end{matrix}\right.\Leftrightarrow x\in\left\{0;1;3\right\}\)
5: Ta có: \(\left|2x+3\right|=x+2\)
\(\Leftrightarrow\left\{{}\begin{matrix}x>=-2\\\left(2x+3+x+2\right)\left(2x+3-x-2\right)=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x>=-2\\\left(3x+5\right)\left(x+1\right)=0\end{matrix}\right.\Leftrightarrow x\in\left\{-\dfrac{5}{3};-1\right\}\)
6: |5x-4|=|x+2|
=>5x-4=x+2 hoặc 5x-4=-x-2
=>4x=6 hoặc 6x=2
=>x=3/2 hoặc x=1/3
câu 7 viết v k hiểu
câu 8: |2x-1|=x<=> \(\left[\begin{array}{nghiempt}2x-1=x\\2x-1=-x\end{array}\right.\)=> x=1 hoặc x=1/3
câu 9 |x+2|=2x<=> \(\left[\begin{array}{nghiempt}x+2=-2x\\x+2=2x\end{array}\right.\)=> x=-2/3 hặc x=-1/2
Câu 7 :
\(\left|\frac{1}{4}x-\frac{3}{4}\right|=\frac{4}{5}x-\frac{2}{5}\)
\(\Rightarrow\) \(\left[\begin{array}{nghiempt}-\frac{1}{4}x+\frac{3}{4}=\frac{4}{5}x-\frac{2}{5}\\\frac{1}{4}x-\frac{3}{4}=\frac{4}{5}x-\frac{2}{5}\end{array}\right.\) \(\Leftrightarrow\) \(\left[\begin{array}{nghiempt}\frac{21}{20}x=\frac{23}{20}\\\frac{11}{20}x=-\frac{7}{20}\end{array}\right.\)
\(\Leftrightarrow\) \(\left[\begin{array}{nghiempt}x=\frac{23}{21}\\x=-\frac{7}{11}\end{array}\right.\)
Cây 8) 9) dễ hơn, bạn làm tương tự
7) | 1/4x - 3/4| = 4/ 5 x- 2/5
Th1:
1/4x - 3/4 = 4/ 5 x- 2/5
1/4x - 4/5x = -2/5 + 3/4
-11/20x = 7/20
x= -7/11
Th2:
1/4x - 3/4 = -(4/ 5 x- 2/5)
1/4x + 4/5x = 3/4 + 2/5
21/20x = 23/20
x= 23/21
Vậy...
8) | 2x-1| =x
Th1:
2x -1 = x
x= 1
Th2:
2x -1 = -x
3x = 1
x= 1/3
Vậy...
9) | x+ 2| = 2x
Th1:
x+2 = 2x
x= 2
Th2:
x+2 = -2x
3x =2
x= 2/3
Vậy...
7) | 1/4x - 3/4| = 4/ 5 x- 2/5
Th1:
1/4x -3/4 = 4/5x -2/5
1/4x - 4/5x = -2/5 + 3/4
(1/4 - 4/5)x = 7/20
-11/20x = 7/20
x= 7/20 : (-11/20)
x= -7/11
Th2:
1/4x - 3/4 = -(4/5x - 2/5)
1/4x - 3/4 = -4/5x + 2/5
1/4x + 4/5x = 2/5 + 3/4
(1/4 + 4/5)x = 23/20
21/20x = 23/20
x= 23/20 : 21/20
x= 23/21
8) | 2x-1| =x
Th1:
2x -1 = x
2x - x= 1
(2-1)x=1
x= 1
Th2:
2x -1 = -x
2x +x = 1
(2+1)x =1
3x =1
x= 1:3
x= 1/3
Vậy...
Còn câu 9 chiều gửi cho