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a,
128-3x-12=23
3x=128-12-23
3x=93
x=93:3
= 31
b,
(12x+84+55):5=35
12x+84+55=35.5
12x+84+55=175
12x=175-55-84
12x=36
x=36:12
x=3
128 - 3(x + 4) = 23
=> 3(x + 4) = 128 - 23
=> 3(x + 4) = 105
=> x + 4 = 105 : 3
=> x + 4 = 35
=> x = 35 - 4
=> x = 31
Vậy x = 31
[(4x + 28) . 3 + 55] : 5 = 35
=> (4x + 28) . 3 + 55 = 35 . 5
=> (4x + 28) . 3 + 55 = 175
=> (4x + 28) . 3 = 175 - 55
=> (4x + 28) . 3 = 120
=> 4x + 28 = 120 : 3
=> 4x + 28 = 40
=> 4x = 40 - 28
=> 4x = 12
=> x = 12 : 4
=> x = 3
Vậy x = 3
1. 128 - 3.(x+4) = 23
3.(x+4) = 5
x+4 = 5 : 3
x+4 = 5/3
x = -7/3
a: =>3(x+4)=115
=>x+4=115/3
hay x=103/3
b: =>\(8^3\cdot\left(12x-64\right)=4\cdot8^4\)
\(\Leftrightarrow12x-64=32\)
=>12x=96
hay x=8
c: \(\Leftrightarrow\left(4x+28\right)\cdot23+55=175\)
=>(4x+28)x23=120
=>4x+28=120/23
=>4x=-524/23
hay x=-131/23
128-3.(x+4) =23
3.(x+4) =128-23
3.(x+4) = 105
x+4 =105:3
x+4 =35
x = 35-4
x=31
a, 128 – 3(x+4) = 23
b, 12 x - 4 3 . 8 3 = 4 . 8 4
c, [(4x+28).3+55]:5 = 35
d, 720:[41 – (2x – 5)] = 2 3 . 5
\(\left(5\cdot x+7\right):2=16\) \(128-3\cdot\left(x-4\right)=23\)
\(\left(5\cdot x+7\right)=16\cdot2\) \(3\cdot\left(x-4\right)=128-23\) \([\left(4\cdot x+28\right)\cdot3+55]:5=35\)
\(\left(5\cdot x+7\right)=32\) \(3\cdot\left(x-4\right)=105\) \([\left(4\cdot x+28\right)\cdot3+55]=35\cdot5\)
\(5\cdot x=32-7\) \(x-4=105:3\) \([\left(4\cdot x+28\right)\cdot3+55]=175\)
\(5\cdot x=25\) \(x-4=35\) \(\left(4\cdot x+28\right)\cdot3=175-55\)
\(x=25:5\) \(x=35+4\) \(\left(4\cdot x+28\right)\cdot3=120\)
\(x=5\) \(x=39\) \(\left(4\cdot x+28\right)=120:3\)
\((4\cdot x+28)=40\)
\(4\cdot x=40-28\)
\(4\cdot x=12\)
\(x=12:4\)
\(x=3\)
Chúc bạn hok tốt !
a) 5x X+7=16x2 b)3x(X-4)=128-23 c)(4x X +28 ) x 3 + 55 = 35 x 5
5xX+7=32 3x(X-4)=105 (4x X + 28) x3 +55 =175
5xX=32-7 X-4 = 105 : 3 (4x X + 28 ) x3 = 175 -55
5xX=25 X-4 = 35 (4x X + 28 ) x3 = 120
X=25:5 X = 35 + 4 4x X + 28 = 120 : 3=40
X=5 X = 39 X = (40-28):4=3